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Nata [24]
3 years ago
9

PLeAsEeeeEeEeeEeEEeEeeeEee. help me with my last questions

Mathematics
2 answers:
Dominik [7]3 years ago
6 0
What were the steps from your last questions
kupik [55]3 years ago
4 0

Answer:

what questions

Step-by-step explanation:

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Whats the answer to this problem 9x+10=2001-X
Vilka [71]

Answer: x=1991/10

Step-by-step explanation: Step 1: Simplify both sides of the equation.

9x+10=2001−x

9x+10=2001+−x

9x+10=−x+2001

Step 2: Add x to both sides.

9x+10+x=−x+2001+x

10x+10=2001

Step 3: Subtract 10 from both sides.

10x+10−10=2001−10

10x=1991

Step 4: Divide both sides by 10.

10x

10

=

1991

10

x=

1991

10

5 0
3 years ago
Read 2 more answers
Pl help it’s for a grade
Alla [95]

Answer:

c

Step-by-step explanation:

5 0
3 years ago
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What value scarified the inequality -2x + 8 + 5x > 2x + 1?
shutvik [7]

Answer:

\boxed{x > -7}

Step-by-step explanation:

\begin{array}{rcll}-2x +8 + 5x & > & 2x + 1 & \\3x + 8 & > & 2x + 1 & \text{Simplified}\\x + 8 & > &1 & \text{Subtracted 2x from each side}\\x  & > & -7 & \text{Subtracted 8 from each side }\\\end{array}\\\boxed{\mathbf{x > -7}} \text{ satisfies the inequality}

8 0
3 years ago
Suzanne has purchased a car with a list price of $23,860. She traded in her previous car, which was a Dodge in good condition, a
Alinara [238K]
The interest is 11.62% compounded monthly. Converting this to an effective rate:
i = (1 + 0.1162/12)^12 - 1
i = 0.1226

We use this formula to solve the problem:
455.96 = (23860(1.0811) + 1695 + 228 - C) [0.0811(1+0.0811)^3]/[(1+0.0811)^3 - 1]
Solving for C
C = 4413.13

The cost of her car was $4,413.13.
3 0
3 years ago
Read 2 more answers
In which quadrant does O lie if the following statements are true:<br> cos 0 &lt; 0 and cscO &gt; 0
Olin [163]

Answer:

2nd quadrant.

Step-by-step explanation:

\text{Given that,}~ \cos \theta < 0~ \text{and}~ \csc \theta > 0.}\\\\\text{So,}~\cos \theta ~ \text{is negative and}~ \csc \theta ~ \text{is positive.}\\\\\text{In Quadrant II, all other ratios are negative except}~ \sin \theta ~ \text{ and}~ \csc \theta.\\\\\text{Hence, the angle lies in the 2nd quadrant.}~

5 0
2 years ago
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