1. The table has a constant of proportionality of 4, therefore, the perimeter and side length of squares are proportional.
2. Equation for the proportion is, y = 4x.
Perimeter = 48 cm.
<h3>What is the Equation of a Proportional Relationship?</h3>
The equation that defines a proportional relationship is, y = kx, where k is the constant of proportionality between variables x and y.
1. For the table given:
y = perimeter
x = side length
k = constant of proportionality = 8/2 = 16/4 = 24/6 = 4.
Since k is the same all through, the equation can be modelled as y = 4x, which means the perimeter and side length of squares are proportional.
2. Using the equation, y = 4x,the perimeter (y) of a square when its side length is 12 (x) is:
y = 4(12)
y = 48 cm.
The perimeter (y) of the square is: 48 cm.
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The solution is (5,2)
Step-by-step explanation:
From the third column the equation for sum of equivalent system is given as;
8x = 40
divide both sides by 8 to get value of x
8x/8 = 40/8
x=5
Using the value of x in the fifth column's first equation will be;
4x +4y =28
4(5) + 4y =28
20 +4y =28
4y= 28-20
4y=8
divide both sides by 4 to get y
4y/4 =8/4
y=2
The solution is x=5 and y=2 written as (5,2)
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Solving simultaneous equations : brainly.com/question/12647791
Keywords: table, solution, column, original system
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The answer is A because 8 is where you started and each time the x number goes up by on the y number goes down by seven (-7)
Answer: 50%
Step-by-step explanation:
Let x = Total dishes.
Dishes from China = 
Dishes from Japan = 
Total dishes from China and Japan = 
Dishes from other countries 
Percent of dishes from other countries= 
Hence, dishes from other countries = 50%
Given that the terminal side of an <θ intersects the unit circle at the point
![P(\frac{5}{6},\frac{-\sqrt[]{11}}{6})](https://tex.z-dn.net/?f=P%28%5Cfrac%7B5%7D%7B6%7D%2C%5Cfrac%7B-%5Csqrt%5B%5D%7B11%7D%7D%7B6%7D%29)
From the given point P:
![\begin{gathered} x=\frac{5}{6} \\ y=\frac{-\sqrt[]{11}}{6} \\ \text{ s}ince,\text{ x is positive and y is negative, the angle lies in the 4th quadrant} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D%5Cfrac%7B5%7D%7B6%7D%20%5C%5C%20y%3D%5Cfrac%7B-%5Csqrt%5B%5D%7B11%7D%7D%7B6%7D%20%5C%5C%20%5Ctext%7B%20s%7Dince%2C%5Ctext%7B%20x%20is%20positive%20and%20y%20is%20negative%2C%20the%20angle%20lies%20in%20the%204th%20quadrant%7D%20%5Cend%7Bgathered%7D)
![\begin{gathered} \tan \theta=\frac{\text{ opposite}}{\text{Adjacent}}=\frac{y}{x} \\ \tan \theta=\frac{\frac{-\sqrt[]{11}}{6}}{\frac{5}{6}}=\frac{-\sqrt[]{11}}{5} \\ \tan \theta=-0.6633 \\ \theta=326.44^0 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctan%20%5Ctheta%3D%5Cfrac%7B%5Ctext%7B%20opposite%7D%7D%7B%5Ctext%7BAdjacent%7D%7D%3D%5Cfrac%7By%7D%7Bx%7D%20%5C%5C%20%5Ctan%20%5Ctheta%3D%5Cfrac%7B%5Cfrac%7B-%5Csqrt%5B%5D%7B11%7D%7D%7B6%7D%7D%7B%5Cfrac%7B5%7D%7B6%7D%7D%3D%5Cfrac%7B-%5Csqrt%5B%5D%7B11%7D%7D%7B5%7D%20%5C%5C%20%5Ctan%20%5Ctheta%3D-0.6633%20%5C%5C%20%5Ctheta%3D326.44%5E0%20%5Cend%7Bgathered%7D)
