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3 years ago

9

? ( Ellen has 2 quarters 1 dime and 1 nickel how many different amounts of money can you make using 1 ore more of these clubs )

HELP!!

1 answer:

ohaa [14]3 years ago

7 0

the answer to this is nine

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Tank 1 initially contains 50 gals of water with 10 oz of salt in it, while tank 2 initially contains 20 gals of water with 15 oz

Naddik [55]

$\dfrac{\mathrm dx_1}{\mathrm dt}=\dfrac{2\text{ oz}}{1\text{ gal}}\dfrac{5\text{ gal}}{1\text{ min}}-\dfrac{x_1(t)\text{ oz}}{50\text{ gal}}\dfrac{5\text{ gal}}{1\text{ min}}$
$\dfrac{\mathrm dx_2}{\mathrm dt}=\dfrac{x_1(t)\text{ oz}}{50\text{ gal}}\dfrac{5\text{ gal}}{1\text{ min}}-\dfrac{x_2(t)\text{ oz}}{20\text{ gal}}\dfrac{5\text{ gal}}{1\text{ min}}$

$\implies\begin{cases}\dfrac{\mathrm dx_1}{\mathrm dt}=10-\dfrac1{10}x_1\\\\\dfrac{\mathrm dx_2}{\mathrm dt}=\dfrac1{10}x_1-\dfrac14x_2\\\\x_1(0)=10\\\\x_2(0)=15\end{cases}$

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3 years ago

At the beginning of the day, stock XYZ opened at $3.15. At the end of the day, it closed at $2.87. What is the rate of change of

natta225 [31]

Answer:

-8.9%

Step-by-step explanation:

3 0

3 years ago

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Suppose that, from measurements in a microscope, you determine that a certain bacterium covers an area of 1.50μm2. Convert this

galben [10]

1 m = 1 x 10⁶ μm
1 m² = (1 x 10⁶)² μm²
1 m² = 1 x 10¹² μm²

area = 1.5 / 1 x 10¹² m²
Area = 1.5 x 10⁻¹² m²

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3 years ago

In a race, a triathlete runs 1/3 of the total distance, cycles 2/5 of the total distance, and swims the remaining distance. He s

liraira [26]

4500 meters. You find this by adding 1/3 and 2/5 which equals 11/15. This means that the remaining 4/15 is 1200 meters long. Divide 1200 by 4 in order to find the distance per 1/15 and you get 300. Multiply 300 with 15 to get the total distance of the race.

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3 years ago

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Javier volunteers in community events each month. He does not do more than five events in a month. He attends exactly five event

enot [183]

Answer:

$P(x < 3) = 25\%$

$E(x) = 3$

Step-by-step explanation:

The given parameters can be represented as:

$\begin{array}{ccccccc}x & {5} & {4} & {3} & {2} & {1}& {0} & P(x) & {25\%} & {30\%} & {20\%} & {15\%} & {5\%} & {5\%} \ \end{array}$

Solving (a): P(x < 3)

This is calculated as:

$P(x < 3) = P(x = 0) + P(x = 1) + P(x =2)$ ----- i.e. all probabilities less than 3

So, we have:

$P(x < 3) = 5\% + 5\% + 15\%$

$P(x < 3) = 25\%$

Solving (b): Expected number of events

This is calculated as:

$E(x) = \sum x * P(x)$

So, we have:

$E(x) = 5 * 25\% + 4 * 30\% + 3 * 20\% + 2 * 15\% + 1 * 5\% + 0 * 5\%$

$E(x) = 125\% + 120\% + 60\% + 30\% + 5\% + 0\%$

$E(x) = 340\%$

Express as decimal

$E(x) = 3.40$

Approximate to the nearest integer

$E(x) = 3$

3 0

3 years ago