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3 years ago

3/5 divided by 1/4 as a word problem

Mathematics

1 answer:

pishuonlain [190]3 years ago

7 0

Answer:

Step-by-step explanation:

12/5 is the answer.

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What is the product of 6s and (-2s²+4s-10)?

Norma-Jean [14]

Answer:

Step-by-step explanation:

Product means multiplication. Since we are multiplying 6s to (-2s²+4s-10), we will use the distributive property to solve.

6s(-2s² + 4s - 10)

-12s³ + 24² - 60

Best of Luck!

7 0

3 years ago

Read 2 more answers

Kenny owned so many baseball cards that he sold 82 of them. After selling the cards he still had 159 left. Write and solve an eq

Anestetic [448]

<span>B. b - 82 = 159; 241 cards
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3 years ago

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Y=(2/11)x+6 line given cross the y-axis

AfilCa [17]

Answer:

$y \gamma \beta \cot( \alpha \sin(?) )$

$\tan( \beta { {x}^{2} }^{?} )$

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2 years ago

Sketch these cartesin products on the x-y plane R^2<br><br> 14. 11,21x1,1.5,2

ale4655 [162]

Answer:

$\left\{11, 21\right\} \times \left\{1, 1.5, 2\right\} = \left\{ (11, 1), (11, 1.5), (11, 2), (21, 1), (21, 1.5), (21, 2)\right\}$

Step-by-step explanation:

The Cartesian product between two discrete sets, is given by all possible ordered pairs originated with the combinations of the elements of the two sets, thus the requested Cartesian product is:

$\left\{11, 21\right\} \times \left\{1, 1.5, 2\right\} = \left\{ (11, 1), (11, 1.5), (11, 2), (21, 1), (21, 1.5), (21, 2)\right\}$

$A = (11, 1)\\B = (11, 1.5)\\C = (11, 2)\\D = (21, 1)\\E = (21, 1.5)\\F = (21, 2)\\$

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3 0

3 years ago

Water is leaking out of an inverted conical tank at a rate of 12,000 cm3/min at the same time that water is being pumped into th

Bas_tet [7]

Answer:

$291111.1cm^3/min$

Step-by-step explanation:

We are given that

$\frac{dV}{dt}_{out}=12000 cm^3/min$

Height of tank,h=6 m

Diameter of top,d=4 m

Radius,r= $\frac{d}{2}=\frac{4}{2}=2 m$

$\frac{dh}{dt}=20 cm/min$

$\frac{r}{h}=\frac{2}{6}=\frac{1}{3}$

$r=\frac{1}{3} h$

We have to find rate at which water is being pumped into the tank.

Volume of conical ,V= $\frac{1}{3}\pi r^2 h$

$V=\frac{1}{3}\pi(\frac{1}{3} h)^2h=\frac{1}{27}\pi h^3$

$\frac{dV}{dt}=\frac{1}{9}\pi h^2(\frac{dh}{dt})$

h=2 m=200 cm

1m=100 cm

$\frac{dV}{dt}_{in}-12000=\frac{1}{9}\pi(200)^2\times 20$

$\frac{dV}{dt}_{in}=12000+\frac{1}{9}\pi (40000)\times 20$

$\frac{dV}{dt}_{in}=291111.1cm^3/min$

4 0

3 years ago