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melamori03 [73]
3 years ago
8

A fuel-air mixture is placed in a cylinder fitted with a piston. The original volume is 0.310-L. When the mixture is ignited, ga

ses are produced and 935 J of energy is released. To what volume will the gases expand against a constant pressure of 635 mmHg, if all the energy released is converted to work to push the piston? □ 12.8 L 114L 9.02L 10.2L
Chemistry
1 answer:
Soloha48 [4]3 years ago
3 0

Answer:

V_2=11.35L

Explanation:

Knowing that the system is at constant pressure, the energy balance is:

\Delta H=Q-W

If all the energy (enthalpy of combustion) is transformed into work:

\Delta H=-W

Work:

W=-\int_{V1}^{V2}P*dV

W=-P*(V_2-V_1)

\Delta H=P*(V_2-V_1)

Calculating:

935J=84659 Pa*(V_2-3.1*10^{-4}m^3)

V_2=0.0113 m^3=11.35L

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