Benzoic acid release protons in water:
C₆H₅COOH(aq) ⇄ C₆H₅COO⁻(aq) + H⁺(aq).
Benzoic acid conjugate base gain protons in water:
C₆H₅COO⁻(aq) + H⁺(aq) ⇄ C₆H₅COOH(aq).
Ka(C₆H₅COOH) = 6.3·10⁻⁵.
Ka · Kb = 1·10⁻¹⁴.
Kb(C₆H₅COO⁻) = 1·10⁻¹⁴ ÷ 6.3·10⁻⁵.
Kb(C₆H₅COO⁻) = 1.587·10⁻¹⁰.
Answer:
A scientific theory is a well-substantiated explanation of some aspect of the natural world that is acquired through the scientific method and repeatedly tested and confirmed, preferably using a written, pre-defined, protocol of observations and experiments.
Explanation:please mark as brainlies
What is the specific heat of a substance whose mass is 7 grams, if it absorbs 180 calories to go from 10 degrees Celsius to 85 degrees Celsius
Answer:
0.343cal/g°C
Explanation:
Given parameters:
Mass of substance = 7g
Quantity of heat absorbed = 180calories
Initial temperature = 10°C
Final temperature = 85°C
Unknown:
Specific heat of the substance = ?
Solution:
To solve this problem, the specific heat of a substance is the amount of heat needed to raise the temperature of a unit mass of that substance by 1°C.
Mathematically;
C = 
C is the specific heat
Q is the amount of heat
m is the mass
T is the temperature
1 and 2 are the initial and final states
Now, insert the parameters and solve;
C = 
= 0.343cal/g°C
Answer:
A and C
Explanation:
both stay the same in every experiment
Answer:
K = 0.2241 M-1 s-1
Explanation:
- 2 NO2(g) → 2NO(g) + O2(g)
- - ra = K*(Ca)∧α = - δCa/δt [=] M/s
∴ a: NO2
∴ α = 2 ....................second order
⇒ - δCa/δt = K Ca²
⇒ - ∫δCa/Ca² = K*∫δt
⇒ [ 1/Ca - 1/Cao ] = K*t
∴ Ca = 0.0463 M
∴ Cao = 0.700 M
∴ t = 90.0 s
rate constant (K):
⇒ - [ 1/0.0463 - 1/0.700 ] = K*(90.0 s)
⇒ 20.1697 M-1 = K*(90.0 s)
⇒ K = 0.2241 M-1 s-1
