Answer:
A) At stage 1 it begins to transmit electrons
B) Electron #2 because it jumped from level 1 to level 4
Explanation:
Welp ur screwed
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<h3>Answer:</h3>
C6H12O6
Explanation:
To find empirical formular you write out the element
Carbon Hydrogen Oxygen
3.96 769 5.28
then u althrough divide by their atomic numbers
3.96÷ 12 769÷1 5.28÷16
=0.33 =769 =0.33
also divide althrough by the lowest number
the lowest number is 0.33 so we use it to divide
0.33÷0.33. 769÷0.33. 0.33÷0.33
= 1 = 2 = 1
empirical formular= CH2O
To find the Molecular formular
Molecular number = molar mass
(CH2O)n = 182
(12+1×2+16)n = 182
30n = 182
n = 6
therefore the Molecular formular is C6H12O6
Answer:
40:1 is the ratio of the magenta phenolphthalein concentration to the colorless phenolphthalein concentration.
Explanation:
To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:
![pH=pK_a+\log(\frac{[salt]}{[acid]})](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%28%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D%29)
![pH=pK_a+\log(\frac{[magenta(Php)]}{[Php]})](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%28%5Cfrac%7B%5Bmagenta%28Php%29%5D%7D%7B%5BPhp%5D%7D%29)
We are given:
= negative logarithm of acid dissociation constant of phenolphthalein = 9.40
= concentration of magenta phenolphthalein
= concentration of colorless phenolphthalein
pH = 11
Putting values in above equation, we get:
![11=9.40+\log(\frac{[magenta(Php)]}{[Php]})](https://tex.z-dn.net/?f=11%3D9.40%2B%5Clog%28%5Cfrac%7B%5Bmagenta%28Php%29%5D%7D%7B%5BPhp%5D%7D%29)
![\log(\frac{[magenta(Php)]}{[Php]})=11-9.40=1.6](https://tex.z-dn.net/?f=%5Clog%28%5Cfrac%7B%5Bmagenta%28Php%29%5D%7D%7B%5BPhp%5D%7D%29%3D11-9.40%3D1.6)
![\frac{[magenta(Php)]}{[Php]}=10^{1.6}=39.81 :1 \approx 40:1](https://tex.z-dn.net/?f=%5Cfrac%7B%5Bmagenta%28Php%29%5D%7D%7B%5BPhp%5D%7D%3D10%5E%7B1.6%7D%3D39.81%20%3A1%20%5Capprox%2040%3A1)
40:1 is the ratio of the magenta phenolphthalein concentration to the colorless phenolphthalein concentration.