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Maru [420]
3 years ago
10

How many kilojoules are needed to raise the temperature of 234 g of water from 19.8 C to 33.1 C?

Chemistry
1 answer:
xenn [34]3 years ago
5 0

Answer:

13 kJ

Explanation:

Use the following formula where Q is the Joules needed, m is the mass of the substance, c is the heat capacity, and ΔT is the change in temperature.

Q = mcΔT

The heat capacity of water is 4.186 J/g°C.  The mass of water is 234 g.  The change in temperature is 13.3°C.

Q = mcΔT

Q = (234 g)(4.186 J/g°C)(13.3°C)

Q = 13,027 J

Since the answer is in Joules, convert to kiloJoules.

13,027 J  =  13.027 kJ  ≈  13 kJ

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Thinking and questioning is the start of the scientific inquiry process. Please select the best answer from the choices provided
aev [14]
Yes thats true! You always have to think about the question or project before you start a science experiment! :) 




8 0
3 years ago
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The isotope 106 46Pd (106 on top and 46 on bottom)
vazorg [7]

Answer:

4. 60 neutrons.

Explanation:

The given isotopes;

         ¹⁰⁶₄₆Pd

In this isotope, we can deduce that the mass number is the superscript and the atomic number is the subscript;

     Mass number  = 106

     Atomic number  = 46

Mass number is the number of protons and neutrons in an atom;

       Mass number = Protons + neutrons

Atomic number is the number of protons

   

So,  Number of protons  = 46

Number of neutrons  = Mass number  - Atomic number

                                    = 106  - 46

                                     = 60

Number of neutrons  = 60

7 0
3 years ago
A and b are two gases that are mixed together: 2.50 mol a is mixed with 0.850 mol b. if the final pressure of the mixture is 1.7
USPshnik [31]

Partial pressure of gas A is 1.31 atm and that of gas B is 0.44 atm.

The partial pressure of a gas in a mixture can be calculated as

Pi = Xi x P

Where Pi is the partial pressure; Xi is mole fraction and P is the total pressure of the mixture.

Therefore we have Pa = Xa x P and Pb = Xb x P

Let us find Xa and Xb

Χa = mol a/ total moles = 2.50/(2.50+0.85) = 2.50/3.35 = 0.746

Xb = mol b/total moles = 0.85/(2.50+0.85) = 0.85/3.35 = 0.254

Total pressure P is given as 1.75 atm

Pa = Xa x P = 0.746 x 1.75 = 1.31atm

Partial pressure of gas A is 1.31 atm

Pb = Xb x P = 0.254 x 1.75 = 0.44atm

Partial pressure of gas B is 0.44 atm.

Learn more about Partial pressure here:

brainly.com/question/15302032

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6 0
2 years ago
Calculate the oxidation state of the underlined elements of K2 Cr2 O7
Semenov [28]

Answer:

+4

Explanation:

In PbO2, oxygen exhibits an oxidation number of -2 (since it's not a peroxide or superoxide):

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⇒ x + (−2) + (−2) = 0

x = +4

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I hope this helps.

3 0
3 years ago
A radiator contains 10 quarts of fluid, 30% of which is antifreeze. how much fluid should be drained and replaced with pure anti
amm1812
Let x be the volume of fluid removed and the volume of pure antifreeze that is added. The concentration of antifreeze in the fluid is 0.3, the concentration in pure antifreeze is 1 and that in the final solution is 0.4 The volume of the final solution is 10.
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The volume that should be drained is 1/7 quarts
3 0
3 years ago
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