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klemol [59]
3 years ago
15

What is the molecular geometry for CH2Br2?

Chemistry
1 answer:
bezimeni [28]3 years ago
7 0

HCH bond angle is ~110 degrees.

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A motorcycle travel at 6.0 m/s. After 3.0 second, the motorcycle travel at 15.0 m/s. Which of the following was the average acce
Lerok [7]

Hello!

\large\boxed{a = 3m/s^{2}}

Use the following equation to solve for the average acceleration of the motorcycle:

a = \frac{v_{f}-v_{i}}{t}

Plug in the given final, initial velocities, and the time:

a = \frac{15-6}{3}\\\\a = \frac{9}{3}\\\\a = 3m/s^{2}

7 0
3 years ago
This is for chemistry:/
Andreyy89

Answer:

Its the bottom one :) ......

5 0
2 years ago
If 3.6 g of aluminum completely reacts, how much Al2O3 (in grams) can be produced
marissa [1.9K]

The amount in grams of  Al₂O₃ produced is approximately 6.80 g.

Aluminium reacts completely with oxygen(air) to produce Al₂O₃. The reaction can be represented with a chemical equation as follows:

AL + O₂ → Al₂O₃

Let's balance it

4AL + 3O₂ → 2Al₂O₃

4 moles of Aluminium reacts with 3 moles of Oxygen molecules to produce 2 moles of Aluminium oxide. Therefore,

Since, aluminium reacts completely, it is the limiting reagent in the reaction. Therefore,

Atomic mass of AL = 27 g

Molar mass of  Al₂O₃ = 101.96 g/mol

4(27 g) of AL gives 2(101.96 g) of  Al₂O₃

3.6 g of AL will give ?

cross multiply

mass of  Al₂O₃ produced = 3.6 × 203.92 / 108   = 734.112 / 108 = 6.797

mass of  Al₂O₃ produced = 6.80 g.

read more: brainly.com/question/23982245?referrer=searchResults

8 0
2 years ago
How many grams of ammonia must you start with to make 900.00 l of a 0.140 m aqueous solution of nitric acid? assume all the reac
bogdanovich [222]
You need the set of reactions that goes from ammonia to nitric acid.
<span>
1) 4NH3(g)+5O2(g)-->4NO(g)+6H2O(g)

2) 2NO(g)+O2(g)-->2NO2(g)

3) 3NO2(g)+H2O(l)-->2HNO3(aq)+NO(g)

State the ratio of moles of HNO3 to NH3:

4 moles of NH3 produce 4 mole of NO,

4 moles of NO produce 4 moles of NO2

4 moles of NO2 produce 4 * (2 / 3) moles of HNO3 = 8/3 moles of HNO3.

=> (8/3) moles HNO3 : 4 moles NH3

Calculate the number of moles of HNO3 in 900.00 l of 0.140 M solution

M = n / V => n = M * V = 0.140 M * 900.00 liter = 126 moles HNO3

Use proportions:

(</span><span>8/3) moles HNO3 / 4 moles NH3 = 126 moles HNO3 / x

=> x = 126 moles HNO3 * 4 moles NH3 / (8/3 moles HNO3) = 189 moles NH3

Convert moles to grams:

molar mass NH3 = 14 g/mol + 3 * 1g/mol = 17 g/mol

mass in grams = number of moles * molar mass = 189 moles * 17 g/mol = 3213 g

Answer: 3213 g.
</span>
3 0
3 years ago
Calculate volume of carbon dioxide gas if the mass is 88.0 g at 20.0°C and 950mmHg
aivan3 [116]

Answer:

Tam tam fdjknf

Explanation:

ttgtsrttrg

7 0
3 years ago
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