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Y_Kistochka [10]
3 years ago
7

Significant Digits and Scientific Notation Part 1: Determine the number of significant digits in each number and write out the s

pecif significant digits. Submit Part 1 and Part 2 to your professor when completed.
1. 405000.
2. 0.0098.
3. 39.999999.
4. 13.00.
5. 80,000,089.
6. 55,430.00.
7. 0.000033.
8. 620.03080.
Chemistry
1 answer:
MA_775_DIABLO [31]3 years ago
8 0

Answer:

1. 6 significant digits. 2. 2 significant digits. 3. 8 significant digits. 4. 4 significant digits. 5. 8 significant digits. 6. 7 significant digits. 7. 2 significant digits.

Explanation:

All nonzero digits are significant. All zeros before nonzeros are insignificant. All zeros after nonzeros are insignificant unless they are made for precision of some data. So 405000 may have 3 or 6 significant figures. But usually all zero figures after significant digits are significant.

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What is the percent error for the experiment if the actual density is
OLga [1]

Answer:

<h3>The answer is 40.96%</h3>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual density = 2.49g/mL

error = 2.49 - 1.47 = 1.02

We have

p(\%) =  \frac{1.02}{2.49}  \times 100 \\ = 40.96385542...

We have the final answer as

<h3>40.96 %</h3>

Hope this helps you

4 0
3 years ago
Read 2 more answers
When heated, calcium hydroxide and ammonium chloride react to produce ammonia gas, water vapor, and solid calcium chloride.
NNADVOKAT [17]

Answer:

13.73g

Explanation:

mass of reactants = mass of products.

Mass reactants = 5.00 g + 10.00 g = 15.00 g

Mass products = 1.27g + mass of ammonia and water vapor

Mass of ammonia and water vapor

15.00g – 1.27 g = 13.73 g

3 0
2 years ago
Which of the following is not a catalyst? A. Nickel B. Platinum C. Enzymes D. Phosphorus
Mazyrski [523]
The answer would be D because from my research it's the only one that didn't have a catalyst 
6 0
3 years ago
Read 2 more answers
Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimen
olga55 [171]

Answer: Rate law=k[A]^1[B]^2, order with respect to A is 1, order with respect to B is 2 and total order is 3. Rate law constant is 3L^2mol^{-2}s^{-1}

Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Rate=k[A]^x[B]^y

k= rate constant

x = order with respect to A

y = order with respect to A

n = x+y = Total order

a) From trial 1: 1.2\times 10^{-2}=k[0.10]^x[0.20]^y    (1)

From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (2)

Dividing 2 by 1 :\frac{4.8\times 10^{-2}}{1.2\times 10^{-2}}=\frac{k[0.10]^x[0.40]^y}{k[0.10]^x[0.20]^y}

4=2^y,2^2=2^y therefore y=2.

b) From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (3)

From trial 3: 9.6\times 10^{-2}=k[0.20]^x[0.40]^y   (4)

Dividing 4 by 3:\frac{9.6\times 10^{-2}}{4.8\times 10^{-2}}=\frac{k[0.20]^x[0.40]^y}{k[0.10]^x[0.40]^y}

2=2^x,2=2^1, x=1

Thus rate law is Rate=k[A]^1[B]^2

Thus order with respect to A is 1 , order with respect to B is 2 and total order is 1+2=3.

c) For calculating k:

Using trial 1:  1.2\times 10^{-2}=k[0.10]^1[0.20]^2

k=3 L^2mol^{-2}s^{-1}.



6 0
3 years ago
How many atoms are present in 34.69 moles of Mg
shusha [124]
<span>Avogadro's number. 

1 mole of any substance, molecule or element is equal to a certain amount of atom. 

6.022 x 10^23 is the Avogradro's constant. 

Magnesium Oxide is a compound. therefore if you have 30.3 g of it (1 mol), it will have the same number of atoms. 

34.69 moles of MgO has 208.9 x 10^23 number of atoms. 

2.089 x 10^25 is also a correct answer.</span><span>
</span>
7 0
3 years ago
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