Write a balanced equation for rusting. (Assume rust becomes Fe+2)
1 answer:
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The name of the compound by using the <u>IUPAC nomenclature of organic compounds</u> is 1 -octene. The correct option is the last option - 1-octene.
<h3>Nomenclature of Organic compounds</h3>From the question, we are to determine the name of the given molecule.
To name the compound, we will follow the IUPAC rules.
Some of IUPAC rules are
- Find the longest continuous carbon chain. Determine the root name for this parent chain.
- For Alkenes (organic compounds with double bond), number the chain of carbons that includes the C=C so that the C=C has the lower position number. Change “ane” to “ene” and assign a position number to the first carbon of the C=C.
The given compound has 8 carbons and a double bond. The root name of the compound is octane.
By <u>IUPAC rules</u>, the compound is an <u>Octene</u>.
Since the double bond is between carbon-1 and carbon-2. The compound becomes 1-octene.
Hence, the name of the compound by using the <u>IUPAC nomenclature of organic compounds</u> is 1 -octene. The correct option is the last option - 1-octene.
Learn more on Nomenclature of Organic compounds here: brainly.com/question/26754333
The diagram for the compound is attached below.
Answer:
Reaction 1 is balanced but 2 is not balanced , the balance equation are :
1.
2.
Explanation:
Balanced Equations : These are the equation which follows the law of conservation of mass .
The total number of atoms present in reactant is equal to total number of atoms present in product.
1.
This is acid - base type reaction where
act as Acid
act as weak base
Reactant : ,
Number of atoms of :
C = 2 () + 1 (
)
= 2 + 1
= 3
H = 4() + 1 (
)
= 4 + 1
5
O = 2() + 3 (
)
= 5
Na = 1 ()
= 1
Product : ,
,
Number of atoms :
C = 1() + 2(
)
= 1 + 2
= 3
H = 2() + 3(
)
= 2 + 3
= 5
O = 1() + 2(
)
+2(
= 1 + 2 + 2
= 5
Na = 1(
= 1
Number of Na =1 , C = 3 , H= 5 and O =5 in both reactant and product , so it is a balanced reaction
2.
This is double displacement reaction .
Check the balancing in both reactant and products should be :
Na = 2
H = 2
Ca = 1
C = 2
O = 6
Cl = 2