<u>Answer:</u> The volume of carbon dioxide gas at STP for given amount is 106.624 L
<u>Explanation:</u>
We are given:
Moles of carbon dioxide = 4.76 moles
<u>At STP:</u>
1 mole of a gas occupies a volume of 22.4 Liters
So, for 4.76 moles of carbon dioxide gas will occupy a volume of = 
Hence, the volume of carbon dioxide gas at STP for given amount is 106.624 L
Let the ratio of grams of hydrogen per gram of carbon in methane be M, we know that:
M = 0.3357 g / 1 g
Next, lets represent the grams of hydrogen per gram of carbon in ethane be E. The final piece of information we have is:
M / E = 4/3
If we cross multiply,
3M = 4E
Now, substituting the value of M from earlier and solving for E,
E = (3 * 0.3357) / 4
E = 0.2518
There are 0.2518 grams of hydrogen per gram of carbon in ethane.
equal to 1
Explanation:
All conversion factors used in any calculation is usually a ratio that is equal to 1. This is because when 1 is used to multiply or divide any number, the number stays the same.
- Conversion factors are useful in making the simplification of an expression very simple. They are usually ratios of 1.
- It follows that a conversion factor is a number that when multiplied or divided by itself will stay the same.
Learn more:
conversion factor: brainly.com/question/555814
#learnwithBrainly
Because other people cannot see what you are sending to somebody
Answer:
22.73s
Explanation:
The reaction is a second order reaction, we know this by observing the unit of the slope.
rate constant = k = 0.056 M-1s-1
the initial concentration of BrO- [A]o = 0.80 M
time = ?
Final concentration [A]t= one-half of 0.80 M = 0.40M
1 / [A]t = kt + 1 / [A]o
1 / 0.40 = 0.056 * t + 1 / 0.80
t = (2.5 - 1.25) / 0.056
t = 22.73s