<h2>Answer:</h2><h3>Balanced equation:</h3>
2C4H10 + 8O2 → 8CO2 + 10H2O
<h3>Description:</h3>
There should be 8 molecules of oxygen which react with 2 molecules of butane to produce 8 molecules of carbon dioxide and 10 molecules of water.
What are you asking? Id love to help but cant without proper information
Answer:
Explanation:
Hello,
In this case, we use the Avogadro's number to compute the molecules of C2F4 whose molar mass is 100 g/mol contained in a 485-kg sample as shown below:
Best regards,
You should take note that the question is about stability. A compound is stable if it does not easily react with other elements. Hence, its reactivity must be low. As you move down the group, reactivity decreases. So, the halide at the very bottom is the least reactive. It would then be logical that the most stable conjugate base is I⁻ and the least stable conjugate base is the most reactive which is F⁻.
Answer:
break it down and just put the numbers
Explanation:
