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zimovet [89]
3 years ago
10

If scientists had tried to repeat thomosons experiment and found that they could not would thomosons cocnclusion still have been

valid?
Chemistry
1 answer:
lesantik [10]3 years ago
5 0

Answer:

No

Explanation:

The conclusions from Thomoson's claims would be invalid if his experiment could not be replicated.

<em>One of the attributes of a valid experiment in science is replication. That is, an experiment must be repeatable with similar outcomes under similar conditions as the original experiment when independently performed by another scientist. Once an experiment cannot be replicated, the outcomes of such an experiment become invalid in science.</em>

Hence, <u>Thomoson's conclusion would be invalid if his experiment could not be replicated. </u>

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Which is the smallest particle into which water (H2O) in a glass can be broken down and still remain water? A. a water molecule
Gnesinka [82]

Answer:-

A. A water molecule

Explanation:-

A molecule is the smallest particle of a compound that retains all it's chemical properties.

Here H2O is a compound. So the smallest particle that will retain all the chemical properties and still remain water is water molecule.

Atoms Hydrogen and Oxygen both have different chemical properties from water H2O and are thus different.

Hydrogen peroxide is different molecule from water. So it is also not water.

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3 years ago
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A cell is placed in a salt solution that has the same concentration as the inside of the cell. What will happen to the cell?
nata0808 [166]

Answer:

d

Explanation:

4 0
3 years ago
Which of the following chemical formulas contains the most molecules?
maw [93]
C. 2Fe2O3 would be the correct answer!
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3 years ago
Element A has a half-life of 10 days. A scientist measures out 200 g of this substance. After 30 days has passed, the scientist
myrzilka [38]
N=N₀*2^(-t/T)

N₀=200 g
T=10 d
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N=200*2^(-30/10)=25 g

25 g will remain
4 0
3 years ago
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The radioactive decay of a certain sample produced 846 disintegrations per minute. exactly 3.00 days later, the rate of decay wa
Margarita [4]

Answer:

\boxed{\text{1.81 da}}

Explanation:

1. Calculate the decay constant

The integrated rate law for radioactive decay is 1

\ln\dfrac{A_{0}}{A_{t}} = kt

where

A₀ and A_t are the counts at t = 0 and t

k is the radioactive decay constant

\ln \dfrac{846}{269} = k \times 3.00\\\\\ln3.145 = 3.00k\\1.146 = 3.00k\\\\k =\dfrac{1.146}{3}\\\\k = \text{0.382 /da}\\

2. Calculate the half-life

t_{\frac{1}{2}} = \dfrac{\ln2}{k} = \dfrac{\ln2}{0.382} = \text{1.81 da}

The half-life for decay is \boxed{\textbf{1.81 da}}.

3 0
3 years ago
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