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earnstyle [38]
3 years ago
11

cyclohexanol is burned as a fuel, according to the following equation, how many moles of oxygen are needed to produce 13.7 mol o

f carbon dioxide? Type the numeric value only and round to tenths place. 2C6H12O + 17O2 → 12CO2 + 12H2O
Chemistry
1 answer:
lidiya [134]3 years ago
3 0

 The moles  of oxygen  that are needed  to produce 13.7 moles  of  carbon  dioxide  is  21.17  moles  of Oxygen


<u><em>calculation</em></u>

2 C₆H₁₂O  + 17 O₂ → 12 CO₂  +12 H₂O


The moles of O₂  is determined using the mole ratio

that  is for  given equation above   O₂ : Co₂  is 17 :12

therefore the moles of O ₂= 13.7   moles x 17/12 =21.17  moles

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TEA [102]

for the first one it is B OR THE SECOND OPTION

8 0
3 years ago
What is the concentration of a solution formed by diluting 25.0 ml of a 3.2 M NaCl solution to 135.0 ml?
Irina-Kira [14]

Answer:

B) 0.59 M NaCl.

Explanation:

  • It is known that the no. of millimoles of NaCl before dilution = the no. of millimoles of NaCl after dilution.

∵ (MV) before dilution = (MV) after dilution.

<em>∴ M after dilution = (MV) before dilution / V after dilution </em>= (3.2 M)(25.0 mL)/(135.0 mL) = <em>0.5926 M ≅ 0.59 M.</em>

4 0
3 years ago
Read 2 more answers
can anyone help with this mole to mole/mole to grams question? any help would be greatly appreciated! Thanks!
goldenfox [79]

Answer:

Explanation:

a) 3.00 mol Cu x 2 mol Ag/ 1 mol Cu = 6 mol Ag

b) 3.00 mol Cu x 2 mol Ag/1 mol Cu x 107.87g Ag/ 1 mol Ag = 647.22g Ag

c) 3.00 mol Cu x 1 mol Cu(NO3)2/ 1 mol Cu = 3 mol Cu(NO3)2

d) 3.00 mol Cu x 1 mol Cu(NO3)2/ 1 mol Cu x 187.54g/ 1 mol Cu(NO3)2 =562.644g Cu(NO3)2

8 0
3 years ago
How many atoms are in 17 moles of O?
omeli [17]

Answer:

67

Explanation:

5 0
3 years ago
You throw a barbeque for your friends. Before you start the grill, your propane tank has a pressure of 78 psi. When you’re finis
Dvinal [7]

Answer:

b. 485 kPa

Explanation:

Gay-Lussac's law express that the pressure of a gas under constant volume is directly proportional to the absolute temperature. The equation is:

P1T2 = P2T1

<em>P is pressure and T absolute temperature of 1, initial state and 2, final state of the gas</em>

<em>Where P1 = 74psi</em>

<em>T2 = 20°C + 273.15 = 293.15K</em>

<em>P2 = ?</em>

<em>T1 = (95°F -32) * 5/9 + 273.15 = 308.15K</em>

<em />

Replacing:

74psi*293.15K = P2*308.15K

70.4psi

In kPa:

70.4psi * (6.895kPa / 1psi) =

<h3>b. 485 kPa </h3>

4 0
3 years ago
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