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Brrunno [24]
4 years ago
8

Which ONE of the following is an oxidation–reduction reaction? A) PbCO3(s) + 2 HNO3(aq) ––––> Pb(NO3)2(aq) + CO2(g) + H2O(l)

B) Na2O(s) + H2O(l) –––> 2 NaOH(aq) C) SO3(g) + H2O(l) ––––> H2SO4(aq) D) CO2(g) + H2O(l) ––––> H2CO3(aq) E) C2H4(g) + H2(g) ––––> C2H6(g)
Chemistry
1 answer:
sveta [45]4 years ago
8 0

Answer:

E) C₂H₄(g) + H₂(g) ⇒ C₂H₆(g)

Explanation:

Which ONE of the following is an oxidation–reduction reaction?

A) PbCO₃(s) + 2 HNO₃(aq) ⇒ Pb(NO₃)₂(aq) + CO₂(g) + H₂O(l). NO. All the elements keep the same oxidation numbers.

B) Na₂O(s) + H₂O(l) ⇒ 2 NaOH(aq). NO. All the elements keep the same oxidation numbers.

C) SO₃(g) + H₂O(l) ⇒ H₂SO₄(aq). NO. All the elements keep the same oxidation numbers.

D) CO₂(g) + H₂O(l) ⇒ H₂CO₃(aq). NO. All the elements keep the same oxidation numbers.

E) C₂H₄(g) + H₂(g) ⇒ C₂H₆(g). YES. <u>C is reduced</u> and <u>H is oxidized</u>.

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Answer:

981.82g or 0.982 kg

Explanation:

I believe this is Physics, but okay!

We have to use the Specific Heat Capacity formula here.

Heat energy = mass x specific heat capacity x change in temperature

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Heat energy is measured in Joules so we need to find out how to do this.

To find an amount in Joules, we are given 135g and 0.89J/g°C.

135g x 400°C = 54000 to give us g°C

54000 x 0.89 = 48060  By multiplying these two values, we get given 48060J.

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Answer:

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6 0
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