Calculate the pH of a solution with [OH−]=1.3×10−2M. (Hint: Begin by using Kw to find [H3O+].)
1 answer:
Answer:
12.11.
Explanation:
∵ pOH = - log[OH⁻]
<em>∴ pOH</em> = - log(1.3 x 10⁻²) = <em>1.886.</em>
∵ pH + pOH = 14.
<em>∴ pH = 14 - pOH</em> = 14 - 1.886 = <em>12.11.</em>
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