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Goryan [66]
3 years ago
7

Calculate the pH of a solution with [OH−]=1.3×10−2M. (Hint: Begin by using Kw to find [H3O+].)

Chemistry
1 answer:
Nookie1986 [14]3 years ago
3 0

Answer:

12.11.

Explanation:

∵ pOH = - log[OH⁻]

<em>∴ pOH</em> = - log(1.3 x 10⁻²) = <em>1.886.</em>

∵ pH + pOH = 14.

<em>∴ pH = 14 - pOH</em> = 14 - 1.886 = <em>12.11.</em>

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