All categories

2 years ago

How many moles are in 8.32 × × times 10^24 molecules of co2?

Chemistry

1 answer:

Gnom [1K]2 years ago

7 0

Answer:

13.8 moles

Explanation:

You know that in a mole you have 6.022x10²³ something in this case of molecules. By knowing that by each mole you have 6.022x10²³ molecules, then you can establish the factor of conversion:

8.32x10²⁴molec of CO2 x 1 mol/6.022x10²³ molec of CO2

You divide 8.32x10²⁴/6.022x10²³ and you get 13.81 moles.

You might be interested in

What is considered to be an unsafe level of lead in flint michigan water?

Olenka [21]

Answer:

More than 40 percent measured above 5 ppb of lead, which the researchers considered an indication of a “very serious” problem.

7 0

3 years ago

What is the name of the compound with the formula B2C14?

agasfer [191]

Answer:

Diboron tetrachloride ---> B2Cl4

6 0

3 years ago

What does the word "kinetic" indicate about

Natasha2012 [34]

It’s B. The kinetic molecular theory states that matter is made up of constantly moving particles.

4 0

2 years ago

Please help! trying to past :((

Margaret [11]

the block will move to F but at the same time make it's way over to G because 250g weighs more than 100g

3 0

3 years ago

what is the pH of a solution that results when 0.010mol HNO3 is added to 500.ml of a solution that is 0.10M in aqueous ammonia a

WARRIOR [948]

Answer : The

pH of a solution is, 8.56

Explanation : Given,

$K_b=1.8\times 10^{-5}$

Concentration of ammonia (base) = 0.10 M

Concentration of ammonium nitrate (salt) = 0.55 M

First we have to calculate the value of $pK_b$ .

The expression used for the calculation of $pK_b$ is,

$pK_b=-\log (K_b)$

Now put the value of $K_b$ in this expression, we get:

$pK_b=-\log (1.8\times 10^{-5})$

$pK_b=5-\log (1.8)$

$pK_b=4.7$

Now we have to calculate the pOH of buffer.

Using Henderson Hesselbach equation :

$pOH=pK_b+\log \frac{[Salt]}{[Base]}$

Now put all the given values in this expression, we get:

$pOH=4.7+\log (\frac{0.55}{0.10})$

$pOH=5.44$

The pOH of buffer is 5.44

Now we have to calculate the pH of a solution.

$pH+pOH=14\\\\pH+5.44=14\\\\pH=14-5.44\\\\pH=8.56$

Thus, the pH of a solution is, 8.56

8 0

3 years ago