Answer:
-943J or 943J released
Explanation:
m=2.4 mol x 207.g/ mol=497.3g
c=.129 J/gC
T= T f-Ti=(22.5-37.2)=-14.7C
Q=?
Q=(49.3g)(.129 J/g C) (-14.7 C)
= -943 J or 943 J released
The reactant in a chemical process known as the limiting reactant controls how much product can be produced. When the limiting reactant is completely used up, the reaction will come to an end.
<h3>
Find the limiting reactant ?</h3>
- As a result of 1 mol Sb4O6 reacting with 6 mol H2SO4, only 0.1 mol Sb4O6 reacts with 0.6 mol H2SO4, leaving only 0.5 mol H2SO4. This indicates that H2SO4 is the limiting reactant and Sb4O6 is present in excess.
- According to your equation, which is balanced, 0.1 mol Sb4O6 should react with 0.6 mol H2SO4, yet there is only 0.5 mol H2SO4 on hand.
- Therefore, only.083 mol of Sb4O6 are reacted.
- The reactant that is present in the limiting amount—the limiting reactant—determines the extent to which a chemical reaction occurs.
- The trick is really quite easy! We employ an augmented matrix to hold the data derived from the balancing equation Sb4O6 + 6H2SO4 --> 2Sb2(SO4)3 + 6H2O.
- Although you are provided 0.5 mol of H2SO4, the reaction requires 0.6 mol. Therefore, the limiting reactant is H2SO4.
- Only 0.0833 mol of Sb4O6 is required, but you have 0.1 mol. Sb4O6 is therefore the extra reactant.
To learn more about limiting reactant refer to:
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Answer:
K2CrO4
Explanation:
To find the empirical formula, we need to divide each element by its atomic mass. The atomic masses of potassium, chromium and oxygen are 39.0983, 51.9961 and 15.999 respectively. We make the divisions as follows:
K = 1.04/39.0983 = 0.027
Cr = 0.70/51.9961 = 0.013
O = 0.86/15.999 = 0.054
We now divide by the smallest which is the number of moles of the Chromium
K = 0.027/0.013 = 2
Cr = 0.013/0.013 = 1
K = 0.054/0.013 = 4 approximately
The empirical formula is thus:
K2CrO4
Answer:
valence electron
Explanation:
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