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Vika [28.1K]
3 years ago
13

When 2 moles of NH3(g) react with N2O(g) to form N2(g) and H2O(g) according to the following equation, 880 kJ of energy are evol

ved. 2NH3(g) + 3N2O(g)4N2(g) + 3H2O(g) Is this reaction endothermic or exothermic? What is the value of q? kJ An error has been detected in your answer. Che
Chemistry
1 answer:
Naily [24]3 years ago
5 0

Answer:

The reaction is an exothermic reaction .

The value of q is -880 kilo Joules.

Explanation:

Exothermic reactions are defined as the reactions in which energy of reactants is more than the energy of the products. In these reactions, energy is released by the system. The total enthalpy of the reaction (\Delta H) comes out to be negative.

According to reaction, 2 moles of ammonia when reacts with 3 moles of  nitrous oxide to give 4 moles of nitrogen gas and 3 moles of water vapor, along with release of 880 kJ of heat energy.

Since, heat is evolved during the course of reaction which means that reaction is an example of Exothermic reaction.

2NH_3(g)+3N_2O(g)\rightarrow 4N_2(g)+3H_2O(g),\Delta H=-880 kJ

The reaction is an exothermic reaction .

The value of q is -880 kilo Joules.

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During a skin burn from an oven, approximate the skin and tissue layer to be infinitely thick compared to the damaged layer. The
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Answer:

The depth of the damage is given as x   = 1.357*10^{-3}m

Explanation:

From Fick's second law

                 \frac{C_{x}-C_{0}}{C_{s}-C_{0}} = 1 -erf [\frac{x}{2\sqrt{Dt} } ] ...(1)

Where

 C_x is the temperature when the skin is damage

 C_0 is the initial temperature of the skin

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  D is the thermal diffusivity

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From the question we are given that

            C_x  = 62°C

           C_0   = 33°C

            D   =  2.5 * 10^{-7} m^2/s.

Substituting values into equation one

                    \frac{62-33}{200-33} = 1 -erf [\frac{x}{2\sqrt{2.5*10^{-7}} *2} ]

                  erf[\frac{x}{1.414*10^{-3}} ] = 0.826\\

       Let assume that  z =\frac{x}{1.414*10^{-3}} ...  (2)

Hence

           erf(z) = 0.826

Looking at the table of error function shown on the first uploaded image

 We can use interpolation to obtain the value of z in this manner

                  \frac{z-0.95}{0.8260-0.8209}  = 1        

                     z = 0.96

 Substituting the value of z into equation 2

           0.96 = \frac{x}{1.414*10^{-3}}

             x   = 1.357*10^{-3}m

               

 

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