A closed gas system initially has pressure and volume of 0.922 atm and 4.64L with the temperature unknown. If the same closed sy
stem has values of 1030 torr, 4.36 L, and 837K, what was the initial temperature in K?
1 answer:
Answer:
606.09K
Explanation:
Using the combined gas law equation;
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressure (atm)
P2 = final pressure (atm)
V1 = initial volume (L)
V2 = final volume (L)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the provided information in the question;
P1 = 0.922atm
P2 = 1030torr = 1.355atm
V1 = 4.64L
V2 = 4.36L
T1 = ?
T2 = 837K
Using P1V1/T1 = P2V2/T2
0.922 × 4.64/T1 = 1.355 × 4.36/837
4.278/T1 = 5.9078/837
Cross multiply
5.9078T1 = 837 × 4.278
5.9078T1 = 3580.69
T1 = 3580.69/5.9078
T1 = 606.09K
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