Answer:
The standard enthalpy of formation of HgO is -90.7 kJ/mol.
Explanation:
The reaction between Hg and oxygen is as follows.
From the given,
Molar mass of HgO = 216.59 g/mol
Mass of HgO decomposed = 18.5 g
Amount of heat absorbed = 7.75 kJ
From the reaction,
The standard enthalpy of formation = 
During the decomposition of 1 mol of HgO , 90.7 kJ of energy absorbed.
For the formation of 1 mol of HgO , 90.7 kJ of energy is release
Therefore, the enthalpy of formation of mercury(II)Oxide is -90.7 kJ/mol
Answer:
Explanation:
Molar mass of As2S3= {75(2) + 32(3)}
= 150 + 96 = 246g/mol
Amount = 3.25mole
And
Amount = mass/ molar mass
mass = amount × molar mass
Mass = 3.25 × 246
mass = 799.5g
Deep under Jupiter's<span> clouds is a </span>huge<span> ocean of liquid metallic hydrogen. On Earth, hydrogen is usually gas. But on </span>Jupiter<span>, the </span>pressure<span> is so great inside its atmosphere that the gas becomes liquid. As </span>Jupiter<span> spins, the swirling, liquid metal ocean creates the strongest magnetic field in the solar system.</span>
