A (-5,0) B (0,-2) C (-3,-4)
Answer:
Ix = Iy = 
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is 
. Moment of inertia of quarter disk about its perpendicular is 
.
Now using perpendicular axis theorem, Ix = Iy = 
= .
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
Answer:
The answer is undefined.
Step-by-step explanation:
Slope is found using this equation: y-y1/x-x1. Fill in the coordinates to this equation. It should now look like this. -7--3/-5--5. When subtracting from two negatives, it changes into a positive. For example, -7--3 becomes -7+3, which equals -4. The same thing applies for the second part. -5--5 becomes -5+5, which equals 0. So, your slope is -4/0. However, when a 0 is in the denominator, it becomes undefined. So, the answer is undefined.
Answer: First top box is 2400, 2nd top box is 120
423x6 = 2400 + 120 +18 = 2538
Step-by-step explanation:
Answer: The coordinates of the vertex are : (-1,-2)
Step-by-step explanation: To find the x coordinate, we use the formula:
Xv = -b/2a = -6/(2.3) = -6/6 = -1
Replacing x by -1, we write:
y = 3. (-1)^2 + 6. (-1) +1 = 3 - 6 + 1 = -2
