Answer:
3 because pretend the rest of the numbers are not there it is 3
Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,
P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216.
P(three 5s) = (1 x 1 x 1)/216 = 1/216
P(one 5 or two 5s) = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36
Answer:
The first table is the only table representing a linear function.
Step-by-step explanation:
<em>" You can tell if a table is linear by looking at how X and Y change. If, as X increases by 1, Y increases by a constant rate, then a table is linear. You can find the constant rate by finding the first difference. This table is linear."</em>
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<em>P.S.</em>
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<em>( thanks to G00GLE for the anwers, hat's off to the internet :^) </em>
Answer: Is this a fun fact??? If it is then this is not related to math at all
Step-by-step explanation:
