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3 years ago

A golf ball is sitting on a tee. The ball is struck with a golf club and flies

Physics

2 answers:

Mrrafil [7]3 years ago

4 0

Answer:

c i kn now it is

Explanation:

Lady_Fox [76]3 years ago

3 0

Answer:

the guy above me was right

Explanation:

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When a car moves up a hill with constant

zysi [14]

C gains potential energy

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2 years ago

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A diamond is underwater; A light ray enters one face of the diamond, then travels at an angle of 30 degrees with respect to the

otez555 [7]

According to snells law

n1 sin theta1 = n2 sin theta2
n1 = 1.333 (water)
n2 = 2.42 (diamond)
it is given that theta =30 degrees so
by putting the values we have

1.333 sin theta = 2.42 sin 30 

sin theta = (2.42/1.333) *0.5 =65.2 degree
so our conclusion is

the ray's angle of incidence θ1 on the diamond = 65.2 degree.
hope this helps

4 0

3 years ago

A ball initially at rest rolls down a hill with an acceleration of 3.3 m/s2. If it accelerates for 7.5 s, how far will it move?

goldfiish [28.3K]

Answer:

Ball will move 92.8125 meter along the cliff in 7.5 seconds.

Explanation:

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this case initial velocity = 0 m/s, acceleration = 3.3 $m/s^2$ , we need to calculate displacement when time = 7.5 seconds.

Substituting

$s=0*7.5+\frac{1}{2} *3.3*7.5^2\\ \\ =92.8125 meter$

So ball will move 92.8125 meter along the cliff in 7.5 seconds.

5 0

3 years ago

A policeman is chasing a criminal across a rooftop at 10 m/s. He decides to jump to the next building which is 2 meters across f

valina [46]

Answer:

They will meet at a distance of 7.57 m

Given:

Initial velocity of policeman in the x- direction, $u_{x} = 10 m/s$

The distance between the buildings, $d_{x} = 2.0 m$

The building is lower by a height, h = 2.5 m

Solution:

Now,

When the policeman jumps from a height of 2.5 m, then his initial velocity, u was 0.

Thus

From the second eqn of motion, we can write:

$h = ut + \frac{1}{2}gt^{2}$

$h = \frac{1}{2}gt^{2}$

$2.5 = \frac{1}{2}\times 10\times t^{2}$

t = 0.707 s

Now,

When the policeman was chasing across:

$d_{x} = u_{x}t + \frac{1}{2}gt^{2}$

$d_{x} = 10\times 0.707 + \frac{1}{2}\times 10\times 0.5 = 9.57 m$

The distance they will meet at:

9.57 - 2.0 = 7.57 m

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3 years ago

Hi please, I Have An attachment on Waves, Just two Objective Questions Whoever Answers Will be Marked Brainliest thank you.

kifflom [539]

Answer:

The first answer is W and Z, since they appear to be a period apart. Dont know the second question. I did what I could, hope someone can answer the second.

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3 years ago