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Dvinal [7]
3 years ago
13

Upon impact, bicycle helmets compress, thus lowering the potentially dangerous acceleration experienced by the head. A new kind

of helmet uses an airbag that deploys from a pouch worn around the rider’s neck. In tests, a headform wearing the inflated airbag is dropped onto a rigid platform; the speed just before impact is 6.0 m/s. Upon impact, the bag compresses its full 12.0 cm thickness, slowing the headform to rest. What is the acceleration, in g’s, experienced by the headform?
Physics
1 answer:
Nana76 [90]3 years ago
4 0

Answer:

-15.3g

Explanation:

We can find the acceleration by using the following SUVAT equation:

v^2 - u^2 = 2ad

where:

v = 0 is the final velocity (the headform comes to rest)

u = 6.0 m/s is the initial velocity before the impact

d = 12.0 cm = 0.12 m is the distance covered during the impact

a is the acceleration

Solving for a, we get

a=\frac{v^2-u^2}{2d}=\frac{0^2-6^2}{2(0.12)}=-150.0 m/s^2

Where the negative sign means it is a deceleration.

Now we know that

g=9.8 m/s^2

So we can express the acceleration in units of g:

a=\frac{-150.0}{9.8}=-15.3g

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<u>Answer:</u>

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