The answer is B preserve the front wheel alignment.
Rotation of the Earth contributes to the idea of the Sun setting and rising. The orbit of the Earth around the Sun results in the changing of seasons.
Diagram A is the correct diagram
Answer:
3.7 m
Explanation:
We are given that
Mass of electron,m=![9.1\times 10^{-31} kg](https://tex.z-dn.net/?f=9.1%5Ctimes%2010%5E%7B-31%7D%20kg)
![Speed of electron,v=6.5\time 10^6 m/s](https://tex.z-dn.net/?f=Speed%20of%20electron%2Cv%3D6.5%5Ctime%2010%5E6%20m%2Fs)
Magnetic filed,B=![1.0\times 10^{-5} T](https://tex.z-dn.net/?f=1.0%5Ctimes%2010%5E%7B-5%7D%20T)
Charge on electron,q=![1.6\times 10^{-19} C](https://tex.z-dn.net/?f=1.6%5Ctimes%2010%5E%7B-19%7D%20C)
We have to find the radius of circular path the electron follows.
We know that
Radius of circular path,r=![\frac{mv}{qB}](https://tex.z-dn.net/?f=%5Cfrac%7Bmv%7D%7BqB%7D)
Using the formula
![r=\frac{9.1\times 10^{-31}\times 6.5\times 10^6}{1.6\times 10^{-19}\times 1\times 10^{-5}}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B9.1%5Ctimes%2010%5E%7B-31%7D%5Ctimes%206.5%5Ctimes%2010%5E6%7D%7B1.6%5Ctimes%2010%5E%7B-19%7D%5Ctimes%201%5Ctimes%2010%5E%7B-5%7D%7D)
![r=3.7 m](https://tex.z-dn.net/?f=r%3D3.7%20m)
Hence, the radius of circular path followed by electron=3.7 m