A parallel-plate air capacitor with a capacitance of 260 pF has a charge of magnitude 0.155 μC on each plate. The plates have a
separation of 0.313 mm. What is the potential difference between the plates?
1 answer:
Answer:
The potential difference between the plates is 596.2 volts.
Explanation:
Given that,
Capacitance 
Charge 
Separation of plates = 0.313 mm
We need to calculate the potential difference between the plates
Using formula of potential difference

Where, Q = charge
C = capacitance
Put the value into the formula


Hence,The potential difference between the plates is 596.2 volts.
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