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gregori [183]
4 years ago
10

372x75×46+1×57×38+8=​

Chemistry
2 answers:
Dmitry [639]4 years ago
8 0

Answer:

1285574

Explanation:

372x75×46+1×57×38+8

= 1283400 + 2166 + 8

= 1285574

tensa zangetsu [6.8K]4 years ago
6 0

Answer:

1285574

Explanation:

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True or False? In a C++ floating-point constant, a decimal point is not required if exponential (E) notation is used.
defon

Answer:

The answer is True

Explanation:

This is because they are equivalent and have same number of bit.

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3 years ago
A can of soda sitting on a supermarket shelf is a(n)
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What is the formula of the hydride formed by germanium?
Nadusha1986 [10]

The atoms combine to form compounds to attain stability in nature. The combination of atoms takes place by sharing of electrons between the atoms or complete transfer of electrons from one atom to another. Generally, atoms combine to complete their octet, that is to possess eight electrons in their outer most shell (noble gas configurations) except hydrogen which can attain stability by two electrons in its outer most shell.

Since germanium has 4 electrons in its outer most shell so it needs 4 more electrons to complete its octet and attains the stability. Hydrogen has 1 electron in its outer most shell and it needs only 1 electron to attain stability so, each germanium will combine with 4 hydrogen atoms and thus forming GeH_4 molecule which is stable in nature.

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6 0
3 years ago
Compute the molar enthalpy of combustion of glucose (C6 H12O6 ): C6 H12O6 (s) + 6 O2 (g) → 6 CO2 (g) + 6 H2 O (g) Given that com
lana66690 [7]

Answer:

The molar enthalpy of combustion of glucose is -2819.3 kJ/mol

Explanation:

Step 1: Data given

Mass of glucose = 0.305 grams

Combustion of 0.305 grams causes a raise of 6.30 °C

Calorimeter has a heat capacity of 755 J/°C

Molar mass of glucose = 180.2 g/mol

Step 2: The balanced equation

C6H12O6 (s) + 6O2 (g) → 6CO2 (g) + 6H2O (g)

Step 3:

ΔH = (m * C * ΔT + c(calorimeter) * ΔT)

with m = mass of the solutin = 0.305 grams

with C = heat capacity of water = 4.184 J/g°C

with ΔT = the change in temperature = 6.30 °C

with c(calorimeter) = 755 J/°C

ΔH = 0.305 * 4.184 *6.30 + 755 * 6.30  = 4764.5 J ( negative because it's exothermic)

Step 4: Calculate moles of glucose

Moles glucose = mass glucose / Molar mass glucose

Moles glucose = 0.305 grams / 180.2 g/mol

Moles glucose = 0.00169 moles

Step 5: Calculate molar enthalpy

Molar enthalpy = -4764.5 J / 0.00169 moles

Molar enthalpy = - 2819254.2 J/moles = -2819.3 kJ/moles

The molar enthalpy of combustion of glucose is -2819.3 kJ/mol

5 0
3 years ago
The fluoride rinse in dental offices usually contains sodium fluoride. Sodium fluoride can be prepared from the reaction between
Bad White [126]

The chemical reaction in which number of atoms of each element present in the reactant side is equal to the number of atoms of that element in product side, such reactions are said to be a balanced chemical reaction.

The chemical symbol for sodium is Na.

The chemical symbol for fluorine gas is F_2.

The chemical symbol for sodium fluoride is NaF

The sodium fluoride is prepared from the reaction between sodium metal and fluorine gas can be written as:

Na (s)+F_2(g) \rightarrow NaF(s)

The above reaction is not balanced as the number of fluorine atoms are not same on reactant and product side. So, in order to balance the reaction we will multiply Na with 2 on reactant side and NaF with 2 on product side. Thus, the balanced reaction will be:

2Na (s)+F_2 (g)\rightarrow 2NaF(s)

Thus, the balanced chemical equation is 2Na (s)+F_2 (g)\rightarrow 2NaF(s).

3 0
3 years ago
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