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sweet-ann [11.9K]

3 years ago

5

the coast of California on the western side of the state has a voice climate wild Eastern side of the desert.what could cause th

is diffrence

2 answers:

diamong [38]3 years ago

7 0

fires could cause a big difference in the weather of California

Elanso [62]3 years ago

7 0

I think the answer is B, Mountains prevent moist air from blowing over into the desert.

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If an experiment calls for 0.200mole acetic acid (Hc2H3O2)how many grams of glacial acetic acid do we need?

bija089 [108]

<h3>Molar mass:-</h3>

$\\ \sf\longmapsto HC_2H_3O_2$

$\\ \sf\longmapsto 1u+2(12u)+3(1u)+2(16u)$

$\\ \sf\longmapsto 1u+24u+3u+48u$

$\\ \sf\longmapsto 28u+48u$

$\\ \sf\longmapsto 76u$

$\\ \sf\longmapsto 76g/mol$

No of moles=0.2mol
Given mass=?

$\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:Mass}{Molar\:Mass}$

$\\ \sf\longmapsto 0.2=\dfrac{Given\:mass}{76}$

$\\ \sf\longmapsto Given\:Mass=0.2\times 76$

$\\ \sf\longmapsto Given\:Mass=1.52g$

7 0

3 years ago

Describe the importance of the water cycle in the terms of;

nikitadnepr [17]

Answer:

ii.

Explanation:

Regulating weather patterns

3 0

1 year ago

The radioactive decay of a certain sample produced 846 disintegrations per minute. exactly 3.00 days later, the rate of decay wa

Margarita [4]

Answer:

$\boxed{\text{1.81 da}}$

Explanation:

1. Calculate the decay constant

The integrated rate law for radioactive decay is 1

$\ln\dfrac{A_{0}}{A_{t}} = kt$

where

A₀ and A_t are the counts at t = 0 and t

k is the radioactive decay constant

$\ln \dfrac{846}{269} = k \times 3.00\\\\\ln3.145 = 3.00k\\1.146 = 3.00k\\\\k =\dfrac{1.146}{3}\\\\k = \text{0.382 /da}\\$

2. Calculate the half-life

$t_{\frac{1}{2}} = \dfrac{\ln2}{k} = \dfrac{\ln2}{0.382} = \text{1.81 da}$

The half-life for decay is $\boxed{\textbf{1.81 da}}$ .

3 0

3 years ago

Which of the following are considered pure substance??

Shkiper50 [21]

Answer:

Explanation:

I’m 99.9% sure that it’s an element because it can’t be broken down any more than it already is.

7 0

3 years ago

MgCl2 + AgNO3 → AgCl + Mg(NO3)2

Law Incorporation [45]

Answer:

MgCl2 + 2AgNO3 → 2AgCl + Mg(NO3)2

Explanation:

I'm assuming you want to balance it so...

The first thing I see is that there are two chlorines on the reactant side and one on the product side

Adding a coefficient of 2 would get 2AgCl2

Now there are two silvers on the reactant side, so add a 2 to AgNO3 on the products side. Now they are all balanced.

If that is not what you are looking for let me know!

6 0

2 years ago

Read 2 more answers