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-BARSIC- [3]
3 years ago
15

The fluoride rinse in dental offices usually contains sodium fluoride. Sodium fluoride can be prepared from the reaction between

sodium metal and fluorine gas. Which properly represents the balanced chemical equation for this reaction? Na(s) + f2(g) → naf2(s) na(s) + f(g) → naf(s) 7na(s) + f(g) → na7f(s) 2na(s) + f2(g) → 2na2f(s) 2na(s) + f2(g) → 2naf(s) why is it important to understand this equation? What do you think could happen if this is incorrect? G
Chemistry
2 answers:
MAVERICK [17]3 years ago
6 0

The correct equation is:  

2Na (s) + F₂ (g) → 2NaF (s)

It is essential to understand the equation, as the correct equation results in the proper proportion of the species in the reaction, resulting in the production of the accurate product species. The fluorine is a diatomic gas, so F₂ will demonstrate it in the reaction. NaF is sodium chloride and Na is sodium. Thus, by balancing the equation accurately, one can get to the final equation 2Na (s) + F₂ (g) = 2NaF (s). If this is incorrect, it can result in the production of the inaccurate product.  

Bad White [126]3 years ago
3 0

The chemical reaction in which number of atoms of each element present in the reactant side is equal to the number of atoms of that element in product side, such reactions are said to be a balanced chemical reaction.

The chemical symbol for sodium is Na.

The chemical symbol for fluorine gas is F_2.

The chemical symbol for sodium fluoride is NaF

The sodium fluoride is prepared from the reaction between sodium metal and fluorine gas can be written as:

Na (s)+F_2(g) \rightarrow NaF(s)

The above reaction is not balanced as the number of fluorine atoms are not same on reactant and product side. So, in order to balance the reaction we will multiply Na with 2 on reactant side and NaF with 2 on product side. Thus, the balanced reaction will be:

2Na (s)+F_2 (g)\rightarrow 2NaF(s)

Thus, the balanced chemical equation is 2Na (s)+F_2 (g)\rightarrow 2NaF(s).

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To determine the empirical formula of the compound given, we need to determine the ratio of each element in the compound. To do that we assume to have 100 grams sample of the compound with the given composition. Then, we calculate for the number of moles of each element. We do as follows:<span>
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C       56.79        4.73
H       6.56          6.50
O       28.37        1.77
N      8.28           0.59

Dividing the number of moles of each element with the smallest value, we will have the empirical formula:

</span>         moles                 ratio
C       4.73     / 0.59       8
H       6.50     / 0.59      11
O       1.77     / 0.59       3
N        0.59    / 0.59       1<span>
</span><span>
The empirical formula would be C8H11O3N.</span>
8 0
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