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-BARSIC- [3]
3 years ago
15

The fluoride rinse in dental offices usually contains sodium fluoride. Sodium fluoride can be prepared from the reaction between

sodium metal and fluorine gas. Which properly represents the balanced chemical equation for this reaction? Na(s) + f2(g) → naf2(s) na(s) + f(g) → naf(s) 7na(s) + f(g) → na7f(s) 2na(s) + f2(g) → 2na2f(s) 2na(s) + f2(g) → 2naf(s) why is it important to understand this equation? What do you think could happen if this is incorrect? G
Chemistry
2 answers:
MAVERICK [17]3 years ago
6 0

The correct equation is:  

2Na (s) + F₂ (g) → 2NaF (s)

It is essential to understand the equation, as the correct equation results in the proper proportion of the species in the reaction, resulting in the production of the accurate product species. The fluorine is a diatomic gas, so F₂ will demonstrate it in the reaction. NaF is sodium chloride and Na is sodium. Thus, by balancing the equation accurately, one can get to the final equation 2Na (s) + F₂ (g) = 2NaF (s). If this is incorrect, it can result in the production of the inaccurate product.  

Bad White [126]3 years ago
3 0

The chemical reaction in which number of atoms of each element present in the reactant side is equal to the number of atoms of that element in product side, such reactions are said to be a balanced chemical reaction.

The chemical symbol for sodium is Na.

The chemical symbol for fluorine gas is F_2.

The chemical symbol for sodium fluoride is NaF

The sodium fluoride is prepared from the reaction between sodium metal and fluorine gas can be written as:

Na (s)+F_2(g) \rightarrow NaF(s)

The above reaction is not balanced as the number of fluorine atoms are not same on reactant and product side. So, in order to balance the reaction we will multiply Na with 2 on reactant side and NaF with 2 on product side. Thus, the balanced reaction will be:

2Na (s)+F_2 (g)\rightarrow 2NaF(s)

Thus, the balanced chemical equation is 2Na (s)+F_2 (g)\rightarrow 2NaF(s).

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Macromolecules. A very large organic molecule composed of many smaller molecules, 1)Carbohydrates, 2)proteins, 3)lipids, 4)nucleic acids. Three of the four classes of macromolecules that are polymers. 1.Carbohydrates.

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Which of the following are strong electrolytes in water?
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Ionic compounds that ionize completely in water

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A solution is prepared by dissolving 150 mL of ethanol in enough water to make a 500 mL solution. What is the percent by volume
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The percent by volume of ethanol in the solution 30% ((150/500)*100%) based on the Law of Conservation of Mass. The object's mass before a reaction and after a reaction is equal according to the Law of Conservation of Mass. The dissolved ethanol become the part of the solution but it does not decrease its volume.
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A person plugs a power cord into an electrical outlet in the wall. The power cord is covered in black rubber. Which statement is
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Answer:

Electrons would easily move through the person if there was no rubber around the wire.

Explanation:

The black rubber material is an insulator and will not allow the conduction of heat or electrical current through it. Electrical currents are generated by the movement of electrons through materials.

<em>Hence, if there was no rubber covering around the power cord, the person that plugged-in the power cord would have experienced electric shock because electrons would easily move through him/her from the wire. </em>

4 0
2 years ago
A 1.0 L vessel contains 20.0 mol of H2, 18.0 mol of CO2, 12.0 mol of H2O,
Lena [83]

Answer:

The equilibrium constant K is 0.1967

Explanation:

Chemical equilibrium is a state of a reacting system in which no observed  changes over time, even though the reaction continues. It occurs in reversible reactions, where the rate of reaction of reagents to products is the same as that of products to reagents.

The chemical equation can be written as:

a A + b B → c C + d D

Where a, b, c, d are the stoichiometric coefficients of the reaction and A, B, C, D are the symbols or formulas of the different substances involved.

The equilibrium constant K can be defined as the ratio between the product between the concentrations of the products (in equilibrium) raised to their corresponding stoichiometric coefficients, and the product of the concentrations of the reactants (in equilibrium) raised in their corresponding stoichiometric coefficients:

Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }

In this case:

Kc=\frac{[CO]*[H_{2}O] }{[CO_{2}]*[H_{2}]  }

You know that:

  • [CO]=\frac{5.9 moles}{1 L} =5.9 M
  • [H_{2} O]=\frac{12 moles}{1 L} = 12 M
  • [CO_{2} ]=\frac{18 moles}{1 L} =18 M
  • [H_{2} ]=\frac{20 moles}{1L} = 20 M

Replacing:

Kc=\frac{5.9 M*12 M}{18 M*20 M}

Kc= 0.1967

<u><em>The equilibrium constant K is 0.1967</em></u>

7 0
3 years ago
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