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-BARSIC- [3]
3 years ago
15

The fluoride rinse in dental offices usually contains sodium fluoride. Sodium fluoride can be prepared from the reaction between

sodium metal and fluorine gas. Which properly represents the balanced chemical equation for this reaction? Na(s) + f2(g) → naf2(s) na(s) + f(g) → naf(s) 7na(s) + f(g) → na7f(s) 2na(s) + f2(g) → 2na2f(s) 2na(s) + f2(g) → 2naf(s) why is it important to understand this equation? What do you think could happen if this is incorrect? G
Chemistry
2 answers:
MAVERICK [17]3 years ago
6 0

The correct equation is:  

2Na (s) + F₂ (g) → 2NaF (s)

It is essential to understand the equation, as the correct equation results in the proper proportion of the species in the reaction, resulting in the production of the accurate product species. The fluorine is a diatomic gas, so F₂ will demonstrate it in the reaction. NaF is sodium chloride and Na is sodium. Thus, by balancing the equation accurately, one can get to the final equation 2Na (s) + F₂ (g) = 2NaF (s). If this is incorrect, it can result in the production of the inaccurate product.  

Bad White [126]3 years ago
3 0

The chemical reaction in which number of atoms of each element present in the reactant side is equal to the number of atoms of that element in product side, such reactions are said to be a balanced chemical reaction.

The chemical symbol for sodium is Na.

The chemical symbol for fluorine gas is F_2.

The chemical symbol for sodium fluoride is NaF

The sodium fluoride is prepared from the reaction between sodium metal and fluorine gas can be written as:

Na (s)+F_2(g) \rightarrow NaF(s)

The above reaction is not balanced as the number of fluorine atoms are not same on reactant and product side. So, in order to balance the reaction we will multiply Na with 2 on reactant side and NaF with 2 on product side. Thus, the balanced reaction will be:

2Na (s)+F_2 (g)\rightarrow 2NaF(s)

Thus, the balanced chemical equation is 2Na (s)+F_2 (g)\rightarrow 2NaF(s).

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Part 1. A chemist reacted 12.0 liters of F2 gas with NaCl in the laboratory to form Cl2 gas and NaF. Use the ideal gas law equat
galben [10]

The mass of NaCl needed for the reaction is 91.61 g

We'll begin by calculating the number of mole of F₂ that reacted.

  • Volume (V) = 12 L
  • Temperature (T) = 280 K
  • Pressure (P) = 1.5 atm
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Number of mole (n) =?

PV = nRT

1.5 × 12 = n × 0.0821 × 280

18 = n × 22.988

Divide both side by 22.988

n = 18 / 22.988

n = 0.783 mole

Next, we shall determine the mole of NaCl needed for the reaction.

F₂ + 2NaCl —> Cl₂ + 2NaF

From the balanced equation above,

1 mole of F₂ reacted with 2 moles of NaCl.

Therefore,

0.783 mole F₂ will react with = 0.783 × 2 = 1.566 moles of NaCl.

Finally, we shall determine the mass of 1.566 moles of NaCl.

  • Mole = 1.566 moles
  • Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
  • Mass of NaCl =?

Mass = mole × molar mass

Mass of NaCl = 1.566 × 58.5

Mass of NaCl = 91.61 g

Therefore, the mass of NaCl needed for the reaction is 91.61 g

Learn more about stiochoimetry: brainly.com/question/25830314

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All of these are compounds except oxygen because a compound is two or more different elements bonded together.
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If a material mixes readily with water it is describe as HYDROPHILIC. Hydrophilic substances are water loving molecules, there reaction with water is favorable in term of thermodynamics. This type of substance are usually charged and often have ability to get involve in hydrogen bonding. 
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