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timurjin [86]
3 years ago
12

An 82 kg jogger has 810 J of kinetic energy. What is the jogger’s velocity?

Physics
2 answers:
yan [13]3 years ago
3 0
By definition, the kinetic energy is given by:
 k = (1/2) * (m) * (v ^ 2)

 Where,
 m: mass
 v: speed
 Clearing the speed we have:
 v ^ 2 = (2 * k) / m

 v =  \sqrt{(2 * k) / m}
 Substituting values:
 v =  \sqrt{(2 * 810) / 82} 

 v = 4.44 m / s
 Answer:
 
The jogger's velocity is:
 
v = 4.44 m / s
zalisa [80]3 years ago
3 0
On edge its 4.4 and i got it right
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A. Both spheres land at the same time.

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A father fashions a swing for his children out of a long rope that he fastens to the limb of a tall tree. As one of the children
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Answer:

The centripetal acceleration of the child at the bottom of the swing is 15.04 m/s².

                     

Explanation:

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Hence, the centripetal acceleration is:

a_{c} = \frac{v^{2}}{r} = \frac{(9.50 m/s)^{2}}{6.00 m} = 15.04 m/s^{2}

Therefore, the centripetal acceleration of the child at the bottom of the swing is 15.04 m/s².

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A 5 kg ball moving to the right at a speed of 6 m/s strikes another 4 kg
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The 5 kg ball moves 3.78 m/s to the left, and the 4 kg ball moves 7.22 m/s to the right.

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Momentum before = momentum after

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½ m₁ u₁² + ½ m₂ u₂² = ½ m₁ v₁² + ½ m₂ v₂²

m₁ u₁² + m₂ u₂² = m₁ v₁² + m₂ v₂²

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280 m²/s² = 5 v₁² + 4 v₂²

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v₂ = (10 − 5 v₁) / 4

280 = 5 v₁² + 4 [(10 − 5 v₁) / 4]²

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1120 = 20 v₁² + (10 − 5 v₁)²

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0 = (9 v₁ + 34) (v₁ − 6)

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