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Harrizon [31]
3 years ago
5

How is electron movement related to the bonding in sodium chloride?

Physics
2 answers:
irina1246 [14]3 years ago
8 0
I think its c sorry if I’m wrong
Svetllana [295]3 years ago
7 0
I am pretty sure it is C, the other ones don’t make sense.
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A 2-kilogram object falls 3 meters. a. How much potential energy did the object have before it fell? b. How much work was accomp
stiks02 [169]
Below are the answers:

(a) Ep = mass x gravitational acceleration x height 
<span>= 2kg x 9.8ms-2 x 3m </span>
<span>= 58.8J </span>

<span>(b) F = mg </span>
<span>= 2kg x 9.8ms-2 </span>
<span>= 19.6N </span>
<span>W = Fd </span>
<span>= 19.6N x 3m </span>
<span>= 58.8J 
</span>
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
6 0
3 years ago
Charles law increases keep pressure constant then you observe blank
OLga [1]

If you decrease the pressure of a fixed amount of gas, its volume will increase.

7 0
3 years ago
When the mallet hits the ball with an action force, the ball exerts a reaction 1 force on the mallet as explained by: 1) Newton'
aliina [53]

Answer:it should be Newton’s second law

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5 0
2 years ago
Read 2 more answers
Find the magnitude and direction of a force between a 25.0 coulomb charge and a 40.0coulomb charge when they are separated by a
deff fn [24]

Answer:

95.0 colomb

Explanation:

Make sure to understand the concept

6 0
3 years ago
Derive an expression for the gravitational potential energy U(r) of the object-earth system as a function of the object's distan
Drupady [299]

Answer:

U(r)=-\frac{Gm_Emr^2}{2R^3_E}

Explanation:

We are given that

Gravitational force=F_g=\frac{Gm_Emr}{R^3_E}

r=0,U(0)=0

We know that

Gravitational potential energy=-\int F_gdr

U(r)=-\int\frac{Gm_Emr}{R^3_E}dr

U(r)=-\frac{Gm_Em}{R^3_E}\times \frac{r^2}{2}+C

Substitute r=0 ,U(0)=0

0=0+C

C=0

Substitute the value

U(r)=-\frac{Gm_Emr^2}{2R^3_E}

4 0
3 years ago
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