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KengaRu [80]
3 years ago
12

You have a spring with k = 640 N/m connected to a mass with m = 10 kg. You start the system oscillating and measure the velocity

of the mass as it moves through the spring's equilibrium position to be 4 m/s. At what position is the kinetic energy of the system equal to the potential energy?
Physics
1 answer:
sdas [7]3 years ago
4 0

Answer:

X= 0.5 m

Explanation:

Given that

K= 640 N/m

m=10 kg

v= 4 m/s

We know that

kinetic energy of the mass

KE=1/2 m v²

Potential energy

PE=1/2 k X²

Given that kinetic and potential energy are equal

1/2 k X² = 1/2 m v²

k X² =  m v²

Now by putting the values

640  X² = 10 x 4²

X= 0.5 m

So at 0.5 m  kinetic and potential energy will be equal.

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Answer:

It's the third one in the picture ...

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2 years ago
A tube with a cap on one end, but open at the other end, has a fundamental frequency of 130.8 Hz. The speed of sound is 343 m/s
sergey [27]

Answer:

Y = V / f      where Y equals wavelength

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Y1 / Y2 = 2 = f2 / f1      dividing equations

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the new fundamental frequency is 2 * 130.8 = 261.6

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3 years ago
Read 2 more answers
At the end of the movie Titanic, Rose lies on a piece of furniture, floating in the ocean, and Jack drowns. A common objection p
julsineya [31]

Answer:

If jack is in the piece of furniture it would submerge.

Explanation:

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maximum buoacy force = density of liquid × volume submerged× acceleration due to gravity.

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v = area × thickness of pine

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therefore buoancy force = 1025×0.075×9.8 N

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Answer:

First law of motion

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