First of all you know it wiill be a positive slope as both the rise and the run are negative. a negative divided by a negative equals a positive. so you can plot the points (2,3) and (-2,-3) as they will be points on this line. next you take a straight line and place it so that both points are intercepted. then extend the line outwards.
Answer:
Step-by-step explanation:
The dog's route and final facing direction are shown in the attached diagram.
<h3>Turns</h3>
The sequence of facing directions for right turns is ...
{N, E, S, W, N}
The sequence of facing directions for left turns is the reverse:
{N, W, S, E, N}
In total, the dog made 3 right turns and 2 left turns. The net change in facing direction is 3-2 = 1 right turn. The dog's initial facing direction is north, so its final facing direction is east, one right turn from north.
<h3>Distance</h3>
The distances traveled are ...
N 4, E 1, S 5, E 2, N 5.
The net change in position is north (4-5+5) = 4 miles, and east (1 +2) = 3 miles. The distance between the final point and the initial point is the hypotenuse of a right triangle with legs 4 miles and 3 miles. The Pythagorean theorem tells us that distance is ...
c² = a² +b²
c = √(a² +b²) = √(4² +3²) = √25 = 5
The smallest distance between the dog's final and initial points is 5 miles.
B ( i think )
i might be wrong though
<em><u>Solution:</u></em>
Given that:
To find: (fog)(2) and (f + g)(2)
By composite function,
( f o g)(x) = f (g(x))
Substitute g(x) = 4x + 9 in above formula,
( f o g)(x) = f(4x + 9)
To find (fog)(2) substitute x = 2 in above formula
( f o g)(2) = f(4(2) + 9)
( f o g)(2) = f(8 + 9) = f(17)
We know that
<em><u>To find (f + g)(2)</u></em>
We know that,
(f + g)(x) = f (x) + g(x)
Therefore,
(f + g)(2) = f(2) + g(2)
Substitute x = 2 in f(x) and g(x)
Let's say the speed of the plane is "p", and the speed of the wind is "w".
when the plane goes with the wind, is not really going "p" mph fast, is really going "p + w" mph fast, because the wind is adding speed to it.
likewise when the plane is going against the wind, is also not going "p" fast is going "p - w" mph fast. Therefore,