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3 years ago

How many significant figures does .00000004 have

2 answers:

4 0

It contains one significant digit and the rule for this one is that leading zeros in fractions less than one are not significant.

photoshop1234 [79]3 years ago

4 0

Answer:

The number has 1 significant digit.

Step-by-step explanation:

Consider the provided number.

The numbers that contribute to the significance of the total number value are significant figures. All the numbers are significant digit except all leading 0.

Rules:

Non-zero digits are significant.

If the zeros is in between non-zero digits then it will be significant.

If the zeros are leading then they are not significant.
if the zeros are at the right of the last non zero digit then they are significant (Trailing Zero).

Now consider the number .00000004

Since all the zeros are leading that means they are not significant.

The number 4 is a significant digit as it is a non zero number.

Hence, the number has 1 significant digit.

You might be interested in

Find the percent of change. 20 increased to 40

ladessa [460]

Answer:

100% increase

Step-by-step explanation:

Calculate percentage change

from V1 = 20 to V2 = 40

(V2−V1)|V1|×100

=(40−20)|20|×100

=2020×100

=1×100

=100%change

=100%increase

6 0

3 years ago

(5) Find the Laplace transform of the following time functions: (a) f(t) = 20.5 + 10t + t 2 + δ(t), where δ(t) is the unit impul

Aloiza [94]

Answer

(a) $F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

Step-by-step explanation:

(a) $f(t) = 20.5 + 10t + t^2 +$ δ(t)

where δ(t) = unit impulse function

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 f(s)e^{-st} \, dt$

where a = ∞

=> $F(s) = \int\limits^a_0 {(20.5 + 10t + t^2 + d(t))e^{-st} \, dt$

where d(t) = δ(t)

=> $F(s) = \int\limits^a_0 {(20.5e^{-st} + 10te^{-st} + t^2e^{-st} + d(t)e^{-st}) \, dt$

Integrating, we have:

=> $F(s) = (20.5\frac{e^{-st}}{s} - 10\frac{(t + 1)e^{-st}}{s^2} - \frac{(st(st + 2) + 2)e^{-st}}{s^3} )\left \{ {{a} \atop {0}} \right.$

Inputting the boundary conditions t = a = ∞, t = 0:

$F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $f(t) = e^{-t} + 4e^{-4t} + te^{-3t}$

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 (e^{-t} + 4e^{-4t} + te^{-3t} )e^{-st} \, dt$

$F(s) = \int\limits^a_0 (e^{-t}e^{-st} + 4e^{-4t}e^{-st} + te^{-3t}e^{-st} ) \, dt$

$F(s) = \int\limits^a_0 (e^{-t(1 + s)} + 4e^{-t(4 + s)} + te^{-t(3 + s)} ) \, dt$

Integrating, we have:

$F(s) = [\frac{-e^{-(s + 1)t}} {s + 1} - \frac{4e^{-(s + 4)}}{s + 4} - \frac{(3(s + 1)t + 1)e^{-3(s + 1)t})}{9(s + 1)^2}] \left \{ {{a} \atop {0}} \right.$

Inputting the boundary condition, t = a = ∞, t = 0:

$F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

3 0

3 years ago

MATH HELP PLEASE !!!! Tickets to a local movie were sold at $5.00 for adults and $3.00 for students. If 150 tickets were sold fo

Vaselesa [24]

Answer:

A = 80 S =70

Step-by-step explanation:

#Adults tickets = A

#Students tickets = S

A + S = 150

5A (means the price is $5 times the number of Adult tickets) equals the total amount for all of the Adult tickets altogether

3S (means the price is $3 times the number of Student tickets) equals the total amount for all of the students tickets altogether

5A + 3S = 610 (Means adding the total of all the student tickets plus adult tickets will equal $610 for all tickets sold)

Using both equations now, you can use substitution or elimination to solve for one of the variables. Then you can use the variable to substitute to solve the remaining one.

A + S = 150

5A + 3S = 610

Substitution:

A = 150 - S (Rearrange the first equation by moving S to the other side)

Substitute into the other equation

5 (150 - S) + 3S = 610

750 - 5S + 3S = 610 Combine like terms : -2S = -140

Solve for S = 70

Substitute into A + S = 150 A + (70) = 150

A = 80

3 0

3 years ago

Pls help solve question 3

Lelu [443]

Answer:

If m is the midpoint of ab it means am is equal to mb

am = 3x + 8 and mb = 6x-4

and ab = am + mb

first find the value of x by using am = mb

3x + 8 = 6x - 4

8 + 4 = 6x - 3x

12 = 3x

x = 4

ab = 3 (4) + 8

= 12 + 8 = 20 = mb

ab = am + mb

= 20 + 20

so, the value of ab is 40

4 0

2 years ago

Which pair of equations below represent parallel lines? and y = 9 and x = 18 y = 4x + 9 and y = 4x – 9 y = 5x + 15 and y = –5x +

Inessa05 [86]

Answer:

The correct option is 2.

Step-by-step explanation:

The slope of two parallel lines are equal.

The slope intercept form of a line is

$y=mx+b$

Where, m is slope and b is y-intercept.

In option 1, the equation of lines are

$y=9$

$x=18$

The first line is a horizontal line and the second line is a vertical line. Therefore they are not parallel line. Option 1 is incorrect.

In option 2, the equation of lines are

$y=4x+9$

$y=4x-9$

By using the slope intercept form of a line, the slope of first line is 4 and the slope of second line is 4.

Since the slope of both lines are same, therefore both lines are parallel. Option 2 is correct.

In option 2, the equation of lines are

$y=5x+15$

$y=-5x+15$

By using the slope intercept form of a line, the slope of first line is 5 and the slope of second line is -5.

Since the slope of both lines are not same, therefore both lines are not parallel. Option 3 is incorrect.

3 0

2 years ago

Read 2 more answers