I think (7,10)
I hope that I helped ;D
6 sin θ - 3 csc θ = 0
6 sin θ = 3 csc θ = 3/sin θ
6 sin^2 θ = 3
sin^2 θ = 3/6 = 1/2
sin θ = sqrt(1/2)
θ = arcsin(sqrt(1/2)) = 45 degrees.
θ = 45°
Y=3x-4
Hope you get it turned in in time!!!
The true statement about the distribution of any variable model around the mean is (D) The distribution of the variable is the same shape as the distribution of its residual
<h3>The true statement about the
distribution</h3>
From the question, we understand that the distribution of the model is based on its mean or average value.
The above means that the upper and the lower deviations are balanced.
Hence, the true statement about the distribution of any variable model around the mean is (D)
Read more about distribution at:
brainly.com/question/15713806
Common factor of 20= 1,2,4,5,10.......
common factor of 35=1,5,7.............
so here we find that 1 and 5 r the common factors
but the GCF of 20 and 35 is 5
so,
by using GCF the distributive property is : 5(4+7)
