Answer:
t = 106π / 30*2.1
Explanation:
=> 106
=> 106 x 2π/60
=> 106/30π
∝ = -2.1 rad/sec²
=> 0
=
+ ∝t
∴ ( -
) / ∝ = t
t = 106π / 30*2.1
Light of intensity 2.00 W/m2 passes through the pupil of one of your eyes and eventually falls on your retina. The radius of the
1 answer:
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The lowest energy of electron in an infinite well is 1.2*10^-33J.
To find the answer, we have to know more about the infinite well.
<h3>What is the lowest energy of electron in an infinite well?</h3>- It is given that, the infinite well having a width of 0.050 mm.
- We have the expression for energy of electron in an infinite well as,
- where;
- Thus, the lowest energy of electron in an infinite well is,
Thus, we can conclude that, the lowest energy of electron in an infinite well is 1.2*10^-33J.
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Answer:
- The specific mechanical energy of the air in the specific location is 40.5 J/kg.
- The power generation potential of the wind turbine at such place is of 2290 kW
- The actual electric power generation is 687 kW
Explanation:
- The mechanical energy of the air per unit mass is the specific kinetic energy of the air that is calculated using:
where V is the velocity of the air.
- The specific kinetic energy would be:
.
- The power generation of the wind turbine would be obtained from the product of the mechanical energy of the air times the mass flow that moves the turbine.
- To calculate mass flow it is required first to calculate the volumetric flow. To calculate the volumetric flow the next expression would be:
- Then the mass flow is obtain from the volumetric flow times the density of the air:
- Then, the Power generation potential is:
- The actual electric power generation is calculated using the definition of efficiency:
, where η is the efficiency,
is the energy actually produced and,
is the energy input. Then solving for the energy produced: