When the object is at the top of the hill it has the most potential energy. If it is sitting still, it has no kinetic energy. As the object begins to roll down the hill, it loses potential energy, but gains kinetic energy. The potential energy of the position of the object at the top of the hill is getting converted into kinetic energy. Hope this helped. :)
She threw the marshmallow at a speed of around 4.76 m/s.The formula for the horizontal range gives the velocity.
<h3>What is projectile motion?</h3>
The motion of an item hurled or projected into the air, subject only to gravity's acceleration, is known as projectile motion.
The item is known as a projectile, and the course it takes is known as a trajectory. Falling object motion is a simple one-dimensional kind of projectile motion with no horizontal movement.
Given data;
The marshmallow was thrown at a distance of 2 meters
Range,R = 3 m
Initial velocity,u
The angle at which the marshmallow was thrown,θ = 30°
The acceleration due to gravity,g = 9.81 m/s²
The projectile's motion is divided into two parts: horizontal and vertical motion.
![\rm R = \frac{u^2sin2 \theta }{g} \\\\ \rm R = \frac{u^2sin2 \times (30) }{9.81} \\\\ u^2=\frac{2 \times 9.81 }{sin 60^0} \\\\ u^2=22.66 \\\\ u=4.76 \ m/sec](https://tex.z-dn.net/?f=%5Crm%20R%20%3D%20%5Cfrac%7Bu%5E2sin2%20%5Ctheta%20%7D%7Bg%7D%20%5C%5C%5C%5C%20%5Crm%20R%20%20%3D%20%5Cfrac%7Bu%5E2sin2%20%5Ctimes%20%2830%29%20%7D%7B9.81%7D%20%5C%5C%5C%5C%20u%5E2%3D%5Cfrac%7B2%20%5Ctimes%209.81%20%7D%7Bsin%2060%5E0%7D%20%5C%5C%5C%5C%20u%5E2%3D22.66%20%5C%5C%5C%5C%20u%3D4.76%20%5C%20m%2Fsec)
Hence, she throws the marshmallow at a speed of 4.76 m/sec.
To learn more about the projectile motion refer to the link;
brainly.com/question/11049671
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<span>65W * 8h * 3600s/h = 1.9e6 J = 447 Cal </span>
<h3>Answer;</h3>
<u>It would make the lens stronger. </u>
<h3>Explanation;</h3>
- The focal length is the distance between the optical center or the center of the lens to the focal point of a convex or concave lens.
- The power of the convex lens is lens ability to undertake refraction or bend light. It is given as the reciprocal of focal length.
- Power of the lens = 1/ f; therefore the smaller the focal length the higher the power and the larger the focal length the lower the power.
- Thus; decreasing the focal length of a convex lens makes the lens stronger.
Answer:
x = 0.0873 m
Explanation:
given,
length of clothesline = 10 m
the line sags to create an angle that is 1 degree below the horizontal on each end.
As mass is hang at the center the angle made let the deflection be 'x'
as the shirt is hang at the center distance will be equal to 5 m.
now
![tan \theta = \dfrac{d_e}{d}](https://tex.z-dn.net/?f=tan%20%5Ctheta%20%3D%20%5Cdfrac%7Bd_e%7D%7Bd%7D)
![tan \theta = \dfrac{x}{5}](https://tex.z-dn.net/?f=tan%20%5Ctheta%20%3D%20%5Cdfrac%7Bx%7D%7B5%7D)
![tan 1^0 = \dfrac{W}{5}](https://tex.z-dn.net/?f=tan%201%5E0%20%3D%20%5Cdfrac%7BW%7D%7B5%7D)
![W = 5 \times 0.0175](https://tex.z-dn.net/?f=W%20%3D%205%20%5Ctimes%200.0175)
x = 0.0873 m
Hence, the cloth line will be x = 0.0873 m from the original length of the clothesline.