A ball is thrown straight up. At what point does the ball have the most energy? Ignore air resistance.

Physics

1 answer:

barxatty [35]3 years ago

4 0

Answer:

Everywhere; the energy of the ball is the same at all of these points.

Explanation:

A ball is thrown straight up. The total energy of an object remains constant as per the law of conservation of energy. At the highest point the object have only potential energy and at lowest point it have only kinetic energy. As a result, the total energy remains constant.

So, at every point the energy of the ball is the same at all of these points. Hence, the correct option is (d).

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Answer:

$1.06085\times 10^{-10}\ m$

Explanation:

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$L=mvr$

From Bohr's atomic model we have

$L=\dfrac{nh}{2\pi}$

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The centripetal force will balance the electrostatic force

$\dfrac{ke^2}{r^2}=\dfrac{mv^2}{r}\\\Rightarrow \dfrac{ke^2}{r}=mv^2\\\Rightarrow \dfrac{ke^2}{r}=m(\dfrac{nh}{2\pi mr})^2\\\Rightarrow r=\dfrac{n^2h^2}{4\pi^2mke^2}\\\Rightarrow r=\dfrac{1^2\times (6.626\times 10^{-34})^2}{4\pi^2 \times 9.11\times 10^{-31}\times 8.99\times 10^{9}\times (1.6\times 10^{-19})^2}\\\Rightarrow r=5.30426\times 10^{-11}\ m$