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den301095 [7]
3 years ago
12

meg runs a 10-km race in 45 minutes (0.75 hours). what was her speed in kilometers per hour ? a. 7.5 km/hr b. 4.5 km/hr c. 13 km

/hr d. 22 km/hr
Physics
1 answer:
cricket20 [7]3 years ago
3 0
The answer would be C.
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A pirate fires his cannon parallel to the water but 3.5 m above the water. The cannonball leaves the cannon with a velocity of 1
Bumek [7]

Answer:

202.8m

Explanation:

Given that A pirate fires his cannon parallel to the water but 3.5 m above the water. The cannonball leaves the cannon with a velocity of 120 m/s. He misses his target and the cannonball splashes into the briny deep.

First calculate the total time travelled by using the second equation of motion

h = Ut + 1/2gt^2

Let assume that u = 0

And h = 3.5

Substitute all the parameters into the formula

3.5 = 1/2 × 9.8 × t^2

3.5 = 4.9t^2

t^2 = 3.5/4.9

t^2 = 0.7

t = 0.845s

To know how far the cannonball travel, let's use the equation

S = UT + 1/2at^2

But acceleration a = 0

T = 2t

T = 1.69s

S = 120 × 1.69

S = 202.834 m

Therefore, the distance travelled by the cannon ball is approximately 202.8m.

4 0
2 years ago
Which of the following correctly describes the hierarchy that exists in the universe? (3 points)
r-ruslan [8.4K]

Answer:

D.

Explanation:

A solar system is a collection of planets, their moons, and other objects in orbit around a central star.

5 0
3 years ago
When a 12 V battery is connected to a 6 uF capacitor, how much energy is stored
adoni [48]

The energy stored in a capacitor is

E = (1/2) · (capacitance) · (voltage)²

E = (1/2) · (6 x 10⁻⁶ F) · (12 V)²

E = (3 x 10⁻⁶ F) · (144 V²)

<em>E = 4.32 x 10⁻⁴ Joule</em>

(That's 0.000432 of a Joule)

4 0
2 years ago
Why are many mitochondria needed in cells that move, like muscle cells?
Deffense [45]
Muscle cells have to use a lot of energy and the Mitochondria is known as the "power house" of the cell... I would say the number of mitochondria needed is increased because more power and energy is being used in that cell than a normal one (idk if this helps or if that's the answer you were looking for)
3 0
2 years ago
student built a simple heat engine that could lift masses. If the heat engine takes in 300 J of heat and loses 50 J to the envir
k0ka [10]

Answer:

So it will lift the mass by h = 17 m

Explanation:

As per energy conservation we know that

Q_1 = W + Q_2

here we know that

Q_1 = 300 J

Q_2 = 50 J

now we have

W = 300 - 50

W = 250 J

so work done by the engine is 250 J

now we have

W = mgh

250 = 1.5 \times 9.81 \times h

h = 17 m

4 0
3 years ago
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