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Pavel [41]
3 years ago
15

A student is trying to determine if a solution is acidic or basic. She does not have any litmus paper. Which would she most like

ly use to get a reading on her solution? vinegar soap cabbage juice aquarium water
Physics
2 answers:
hammer [34]3 years ago
6 0

The correct answer is C.Cabbage juice

Hitman42 [59]3 years ago
6 0

Answer:

cabbage juice  

Explanation:

Red cabbage has pH indicator pigment. It changes color when mixed with acid or basic solution.

For acidic solution, the juice turns red. For neutral, it shows purple color. For basic solution have pH 8-9 : Blue for 10-11: green and strong basic solutions are indicated when cabbage juice turns yellow in color.

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Can we use a clinical thermometer to measure the temperature of a candle flame​
miv72 [106K]

In theory, yes. The 2 problems are the materials used for clinical thermometers, & the temperature capacity of the clinical thermometer. If anything, change the material & extend the measurement threshold. At that point, it wouldn´t be used for clinical garbage anymore.

3 0
4 years ago
The slope at point A of the graph given below is:<br><br><br> WILL MARK BRAINLIEST TO CORRECT ANSWER
steposvetlana [31]

RQ/PQ I think

rise/run

3 0
3 years ago
A sock stuck to the inside of the clothes dryer spins around the drum once every 2.0 s at a distance of 0.50 m from the center o
Rashid [163]

a) 1.57 m/s

The sock spins once every 2.0 seconds, so its period is

T = 2.0 s

Therefore, the angular velocity of the sock is

\omega=\frac{2\pi}{T}=\frac{2\pi}{2.0}=3.14 rad/s

The linear speed of the sock is given by

v=\omega r

where

\omega is the angular velocity

r = 0.50 m is the radius of the circular path of the sock

Substituting, we find:

v=(3.14)(0.50)=1.57 m/s

B) Faster

In this case, the drum is twice as wide, so the new radius of the circular path of the sock is twice the previous one:

r' = 2r = 1.00 m

At the same time, the drum spins at the same frequency as before, therefore the angular frequency as not changed:

\omega' = \omega = 3.14 rad/s

Therefore, the new linear speed would be:

v'=\omega' r' = \omega (2r)

And substituting,

v'=(3.14)(1.00)=3.14 rad/s = 2v

So, we see that the linear speed has doubled.

8 0
3 years ago
As it rains and snows near mountaintops, the water is transferred from the atmosphere back onto ground. What natural force pulls
Semenov [28]
Gravity pulls the water down off the mountain, witch is run-off.
8 0
4 years ago
A 0.20 kg mass (m1) hangs vertically from a spring and an elongation of the spring of 9.50 cm (r1) is recorded. With a mass (m2)
kupik [55]

Answer:

k=320N/m

Explanation:

Step one:

given data

Let the initial/equilibrum position be x

mass m1= 0.2kg

F1= 0.2*10= 2N

elongation e= 9.5cm= 0.095m

mass m2=1kg

F2=1*10= 10N

elongation e= 12cm= 0.12m

Step two:

From Hooke's law, which states that provided the elastic limits of a material is not exceeded the extention e is proportional to applied Force F

F=ke

2=k(0.095-a)

2=0.095k-ka----------1

10=k(0.12-a)

10=0.12k-ka----------2

solving equation 1 and 2 simultaneously

 

   10=0.12k-ka----------2

-   2=0.095k-ka----------1

   8=0.025k-0

divide both side by 0.025

k=8/0.025

k=320N/m

5 0
3 years ago
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