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Pavel [41]
3 years ago
15

A student is trying to determine if a solution is acidic or basic. She does not have any litmus paper. Which would she most like

ly use to get a reading on her solution? vinegar soap cabbage juice aquarium water
Physics
2 answers:
hammer [34]3 years ago
6 0

The correct answer is C.Cabbage juice

Hitman42 [59]3 years ago
6 0

Answer:

cabbage juice  

Explanation:

Red cabbage has pH indicator pigment. It changes color when mixed with acid or basic solution.

For acidic solution, the juice turns red. For neutral, it shows purple color. For basic solution have pH 8-9 : Blue for 10-11: green and strong basic solutions are indicated when cabbage juice turns yellow in color.

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Why does the moon turn red during a lunar eclipse?.
SOVA2 [1]

Answer:

During a lunar eclipse, the Moon turns red because the only sunlight reaching the Moon passes through Earth's atmosphere. The more dust or clouds in Earth's atmosphere during the eclipse, the redder the Moon will appear.

4 0
3 years ago
Which of the following could be the source of resistance in a household electric circuit?
Tpy6a [65]
D. all of these

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Read 2 more answers
A 5 kgkg sphere having a charge of ++ 8 μCμC is placed on a scale, which measures its weight in newtons. A second sphere having
Mrac [35]

Answer:

 F_Balance = 46.6 N    ,m' = 4,755 kg

Explanation:

In this exercise, when the sphere is placed on the balance, it indicates the weight of the sphere, when another sphere of opposite charge is placed, they are attracted so that the balance reading decreases, resulting in

          ∑ F = 0

          Fe –W + F_Balance = 0

         F_Balance = - Fe + W

           

The electric force is given by Coulomb's law

          Fe = k q₁ q₂ / r₂

The weight is

          W = mg

Let's replace

           F_Balance = mg - k q₁q₂ / r₂

Let's reduce the magnitudes to the SI system

          q₁ = + 8 μC = +8 10⁻⁶ C

          q₂ = - 3 μC = - 3 10⁻⁶ C

          r = 0.3 m = 0.3 m

Let's calculate

         F_Balance = 5 9.8 - 8.99 10⁹  8 10⁻⁶ 3 10⁻⁶ / (0.3)²

         F_Balance = 49 - 2,397

         F_Balance = 46.6 N

This is the balance reading, if it is calibrated in kg, it must be divided by the value of the gravity acceleration.

Mass reading is

          m' = F_Balance / g

          m' = 46.6 /9.8

          m' = 4,755 kg

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