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drek231 [11]
3 years ago
13

In its aqueous solution, 32% of a substance dissociates to release hydroxide ions. Which of the following is true for the substa

nce? It is a weak acid. It is a weak base. It is a strong acid. It is a strong base.
Chemistry
1 answer:
Scrat [10]3 years ago
5 0

The solution is a weak base. a weak base is that which dissociates partially in aqueous solution to give hydroxide ions as the only negatively charged ions. In the provided information, only 32 %of the substance dissociates thus it is a partial dissociation. Most of the energy is used to break bonds thus the remaining energy is not enough to cause complete dissociation.

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Answer:

What is the charge on the barium ion and what is the charge of the hydroxide ion.

Explanation:

To get the correct formula they have to add to zero over all.

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During fusion _____. hydrogen atoms are split apart U-235 atoms are created helium atoms are created uranium atoms are fused tog
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4 0
3 years ago
Read 2 more answers
Propane (c3h8) is burned in oxygen to produce carbon dioxide and water. the heat of combustion of propane is -2012 kj/mole. how
Olegator [25]
C_{3} H_{8} + 5 O_{2} ---\ \textgreater \  3CO_{2}  +4H_{2}O    (-2012 \frac{kJ}{mol} )


3 mol                10 mol


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because 3 mol propane require 15 mol oxygen (by reaction)

5 mol oxygen ---1 mol propane, so

10 mol oxygen ---2 mol propane

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5 0
3 years ago
A pycnometer is a precisely weighted vessel that is used for highly accurate density determinations. Suppose that a pycnometer h
dexar [7]

Answer:

5.758  is the density of the metal ingot in grams per cubic centimeter.

Explanation:

1) Mass of pycnometer = M = 27.60 g

Mass of pycnometer with water ,m= 45.65 g

Density of water at 20 °C = d =998.2 kg/m^3

1 kg = 1000 g

1 m^3=10^6 cm^3

998.2 kg/m^3=\frac{998.2 \times 1000 g}{10^6 cm^3}=0.9982 g/cm^3

Mass of water ,m'= m - M = 45.65 g -  27.60 g =18.05 g

Volume of pycnometer = Volume of water present in it = V

Density=\frac{Mass}{Volume}

V=\frac{m'}{d}=\frac{18.05 g}{0.9982 g/cm^3}=18.08 cm^3

2) Mass of metal , water and pycnometer = 56.83 g

Mass of metal,M' =  9.5 g

Mass of water when metal and water are together ,m''= 56.83 g - M'- M

56.83 g - 9.5 g - 27.60 g = 19.7 g

Volume of water when metal and water are together = v

v=\frac{m''}{d}=\frac{19.7 g}{0.9982 g/cm^3}=19.73 cm^3

Density of metal = d'

Volume of metal = v' =\frac{M'}{d'}

Difference in volume will give volume of metal ingot.

v' = v - V

v'=19.73 cm^3-18.08 cm^3=

v'=1.65 cm^3

Since volume cannot be in negative .

Density of the metal =d'

=d'=\frac{M'}{v'}=\frac{9.5 g}{1.65 cm^3}=5.758 g/cm^3

5 0
3 years ago
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