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Scilla [17]
3 years ago
14

Please please help me with these questions. It’s urgent. I will mark BRAINLIEST.

Mathematics
1 answer:
zmey [24]3 years ago
8 0

Answer:

\large\boxed{Q1.\ \sin\theta=\dfrac{40}{41}}\\\boxed{Q2.\ 30^o}

Step-by-step explanation:

Q1.

\sin\theta=\dfrac{y}{r}

\text{We have}\\\\r=1\to(\text{radius of the unit circle}),\\\\y=\dfrac{40}{41}\to\text{from the given point}\ \left(\dfrac{9}{41},\ \dfrac{40}{41}\right)\\\\\text{Substitute:}\\\\\sin\theta=\dfrac{\frac{40}{41}}{1}=\dfrac{40}{41}

Q2.

<em>look at the picture</em>

210° is in III Quadrant. Therefore the reference angle for θ is:

210° - 180° = 30°

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