Question

Please please help me with these questions. It’s urgent. I will mark BRAINLIEST.

Answer 1

Answer:

$\large\boxed{Q1.\ \sin\theta=\dfrac{40}{41}}\\\boxed{Q2.\ 30^o}$

Step-by-step explanation:

Q1.

$\sin\theta=\dfrac{y}{r}$

$\text{We have}\\\\r=1\to(\text{radius of the unit circle}),\\\\y=\dfrac{40}{41}\to\text{from the given point}\ \left(\dfrac{9}{41},\ \dfrac{40}{41}\right)\\\\\text{Substitute:}\\\\\sin\theta=\dfrac{\frac{40}{41}}{1}=\dfrac{40}{41}$

Q2.

look at the picture

210° is in III Quadrant. Therefore the reference angle for θ is:

210° - 180° = 30°