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3 years ago

Which proportionality applies to Avogadro’s law?

Chemistry

2 answers:

Diano4ka-milaya [45]3 years ago

7 0

Answer:

it's D on edge uwu

Explanation:

Rom4ik [11]3 years ago

3 0

The one which proportionality applies to Avogadro's law is V-n

The law stated that equal volume of all gases at the same temperature and pressure, have the same number of molecules.

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consider the reaction between calcium oxide and carbon dioxide: cao ( s ) + co 2 ( g ) → caco 3 ( s ) a chemist allows 14.4 g of

MakcuM [25]

Answer:

CaO is the limiting reagent

Theoritical yield = 25.71 g

% Yield = 75.44%

Explanation:

1 mole = Molar mass of the substance

Molar Mass of CaO = 56 g/mol

Molar Mass of CaCO3 = 100 g/mol

Molar mass of CO2 = 44 g/mol

The balanced Equation is :

$CaO + CO_{2}\rightarrow CaCO_{3}$

1 mole of CaO reacts with = 1 mole of CO2

56 g of CaO reacts with = 44 g of CO2

1 g of CaO reacts with =

$\frac{44}{56}$

= 0.785 g of CO2

So,

<u>14.4 g of CaO</u><u> </u>must react with = (14.4 x 0.785) g of CO2

= 11.31 g of CO2

<u>Needed = 11.31 g</u>

<u>Available CO2 = 13.8 g</u><u> </u>(given)

So CO2 is in excess , hence<u> CaO is the limiting reagent and product will produce from 14.4 g of CaO</u>

$CaO + CO_{2}\rightarrow CaCO_{3}$

1 mole of CaO will produce 1 mole pf CaCO3

56 g of CaO produce = 100 g of CaCO3

1 g of CaO produce =

$\frac{100}{56}$

= 1.785 g of CaCO3

14.4 g of CaO will produce = (1.785 x 14.4) g of CaCO3

= 25.71 g of CaCO3

Theoritical Yield of CaCO3 = 25.71 g

Actual yield = 19.4 g

Percent Yield =

$\frac{Actual\ yield}{Theoritical\ yield}\times 100$

$\frac{19.4}{25.71}\times 100$

= 75.44 %

6 0

3 years ago

How many calories of heat are needed to raise the temperature of 33.0 g of diethyl ether from 14.0 ∘C to 25.0 ∘C ?

Xelga [282]

The amount of heat (in calories) needed to raise the temperature is 324.885 calories

<h3>How to determine the temperature change </h3>

We'll begin by obtaining the temperature change. This can be obtained as followed:

Initial temperature (T₁) = 14 °C
Final temperature (T₂) = 25 °C
Change in temperature (ΔT) = ?

ΔT = T₂ - T₁

ΔT = 25 - 14

ΔT = 11 °C

<h3>How to determine the heat (in Calories)</h3>

The amount of heat needed to raise the temperature can bee obtaimedals follow:

Mass (M) = 33 g
Change in temperature (ΔT) = 11 °C
Specific heat capacity (C) of diethyl ether = 0.895 cal/g°C
Heat (Q) =?

Q = MCΔT

Q = 33 × 0.895 × 11

Q = 324.885 calories

Thus, the amount of heat needed is 324.885 calories

Learn more about heat transfer:

brainly.com/question/10286596

#SPJ1

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1 year ago

What is the freezing point (in °C) of a 0.743 m

luda_lava [24]

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3 years ago

Which of the following occurs when a large nucleus is split apart?

grin007 [14]

Answer: The correct answer is <u>''fission</u>'' it occurs when a large nucleus is split apart.

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3 years ago

How do the number of protons in U-235 and U-238 compare?

8090 [49]

The number of protons among the 2 isotopes remain the same, what varies is the number of neutrons between the 2 isotopes. The isotope with the larger mass number possess a greater number of neutrons compared to the other one.

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4 years ago