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Yakvenalex [24]
4 years ago
6

Solutions that have more OH– than H+ ions are

Chemistry
1 answer:
NARA [144]4 years ago
3 0
The correct answer is option C. Solutions that have more OH– than H+ ions are bases. These are substances that are slippery to touch and has an astringent taste. It reacts with acids in a neutralization reaction forming salts. It accepts protons. Examples are sodium hydroxide and potassium hydroxide.
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What would be the freezing point of a solution that has a molality of 1.468 m which was prepared by dissolving biphenyl (C12H10)
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Answer:

Freezing point solution = 70.131 °C

Explanation:

Step 1: Data given

Molality = 1.468 molal

A solution is created by dissolving biphenyl (C12H10) into naphthalene

Biphenyl is a non-electrolyte

Freezing point of naphthalene = 80.26 °C

Step 2: Calculate the freezing point depression

ΔT = i*Kf*m

⇒with ΔT = the freezing point depression = TO BE DETERMINED

⇒with i = the van't Hoff factor of biphenyl = 1

⇒with Kf = the freezing point depression constant of naphthalene = 6.90 °C/m

⇒with m = the molality = 1.468 molal

ΔT = 1 * 6.90 °C/m * 1.468 °C

ΔT = 10.13 °C

Step 3: Calculate the freezing point of the solution

ΔT = 10.13 °C

Freezing point solution = freezing point naphthalene - 10.13 °C

Freezing point solution = 80.26 °C - 10.129 °C

Freezing point solution = 70.131 °C

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