Answer:
The particle A will strike on the screen to the right (in -y₀). The particle B will strike to the left of the screen (in y₀), at the same distance than particle A from the x-axis but in the opposite direction. The particle C will strike to the right of the screen (in -y₁), the same direction than particle A, but nearer to the x-axis (see attached image)
The exact positions in the screen are (the point [0,y,0]):
Explanation:
The electric charges that move throw a region of space with a magnetic field will suffer a magnetic force (explain by Lorentz Force law). This force will force the particle to change direction but won't change its speed module. Therefore magnetic force act as a centripetal force.
The Lorentz Force law can be written as:
For particle A:
For particle B:
For particle C:
The force applied in each particle in the module is the same as you can see. Nevertheless, their directions are not. In the case of particles A and C, the force has a negative direction in the y-axis while in case B has a positive direction in the y-axis.
Knowing that the magnetic force is a centripetal force, we can find the radius of curvature:
For particle A:
For particle B:
For particle C:
Now we can obtain the exact point in the screen where the particle will strike. We can see than particle A and C are affected by the same force (same module and direction), but the radius of curvature of particle C is twice the one of particle A. Therefore the particle C will strike nearer to the x-axis than particle A.
In each case we can use Pythagoras Theorem to determine the point Y where the particles strike:
and in the triangle form
Therefore:
Answer:
0.47 N
Explanation:
q1 = 3.4 x 10^-6 C
q2 = 2 x 10^-6 C
d = 17.5 cm = 0.175 m
The electrostatic force is given by
F = 0.47 N
Thus, the force is 0.47 N.
True, I just learned this a week ago. Is this for Chemistry?
Answer: after 1.75 seconds
Explanation:
The only force acting on the ball is the gravitational force, so the acceleration will be:
a = -9.8 m/s^2
the velocity can be obtained by integrating over time:
v = -9.8m/s^2*t + v0
where v0 is the initial velocity; v0 = -7.95 m/s.
v = -9.8m/s^2*t - 7.95 m/s.
For the position we integrate again:
p = -4.9m/s^2*t^2 - 7.95 m/s*t + p0
where p0 is the initial position: p0 = 29m
p = -4.9m/s^2*t^2 - 7.95 m/s*t + 29m
Now we want to find the time such that the position is equal to zero:
0 = -4.9m/s^2*t^2 - 7.95 m/s*t + 29m
Then we solve the Bhaskara's equation:
Then the solutions are:
t = (7.95 + 25.1)/(-9.8) = -3.37s
t = (7.95 - 25.1)/(-9.8) = 1.75s
We need the positive time, then the correct answer is 1.75s
Answer: Frequency is the rate of vibration and oscillation measured over a specific period of time (usually one second). In layman's terms, it's simply a repeating sequence.
Explanation: