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4 years ago

Four patients have been diagnosed with medical issues.

Physics

2 answers:

barxatty [35]4 years ago

7 0

Explanation :

Ultrasonic waves :

Ultrasonic waves are the waves which have frequencies higher than 20 KHz. Dolphins, bats etc produce ultrasonic waves.

Ultrasonic waves have many applications. Some of them are :

It is used to see the development of fetus inside the mother's womb. These waves are passed inside the body and it moves in the tissues of the body. Then the conversion of waves into an electrical signal takes place and images can be taken on the screen.

It is also used to detect the stones in kidneys.

So, using ultrasound technology Ashley's and Ron's medical issues can be diagnosed.

saul85 [17]4 years ago

3 0

Ashley because she’s pregnant and you use a ultrasound to see the baby.

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find the density, in g/cm3g/cm3 , of a metal cube with a mass of 50.3 gg and an edge length (l)(l) of 2.65 cmcm . for a cube v

Alina [70]

The density of the metal cube is 2.703 g/cm³.

The mass of a metal cube is m =50.3 grams.

The edge length of the metal cube is l = 2.65 cm.

Now, the density (ρ) of a cube can be given as:

ρ = m/(a)³

Where (a)³ is the volume of the cube, m is the mass of the cube, ρ is the density of the cube, and a is the length of one side of the cube.

Since the sides of a cube are equal therefore the value of a is the same for each edge length of the cube.

Now, the density of the metal cube in g/cm³ is:

ρ = m / a³

ρ = m / l³

ρ = 50.3 g / (2.65 cm)³

ρ = 50.3 g / (2.65 cm)(2.65 cm)(2.65 cm)

ρ = 50.3 g / 18.609 cm³

ρ = 2.703 g/cm³

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4 0

2 years ago

A person in bare feet is standing under a tree during a thunderstorm, seeking shelter from the rain. A lightning strike hits the

Anni [7]

Answer:

$I=38.181\ A$ is the current through the body of the man.

$E=34.5\ J$ energy dissipated.

Explanation:

Given:

time for which the current lasted, $t=43\times 10^{-6}\ s$

potential difference between the feet, $V=21000\ V$

resistance between the feet, $R=550\ \Omega$

Now, from the Ohm's law we have:

$I=\frac{V}{R}$

$I=\frac{21000}{550}$

$I=38.181\ A$ is the current through the body of the man.

Energy dissipated in the body:

$E=I^2.R.t$

$E=38.181^2\times 550\times 43\times 10^{-6}$

$E=34.5\ J$

5 0

4 years ago

A room that has an average ambient sound pressure level of 62 dBA and a maximum sound pressure level lasting more than a minute

cupoosta [38]

Answer:

Explanation:

A fire alarm notification appliance is an active fire protection component of a fire alarm system. The primary function of the notification appliance is to alert persons at risk.

If want the audible public mode signal to be hear clearly then, we need to have a sound level that is at least 15dB above the average ambient sound level or 5dB above the maximum sound level of at least 1minute

In this case the,

The average ambient sound level is 62dB,

And the maximum sound level is 68dB

Then, the public mode signal should be at least

1. 62dB+ 15dB=77dB

2. 68dB +5dB =73dB.

Then the public mode signal hearing must be at least 77dB.

6 0

4 years ago

Sabe-se que um alqueire paulista equivale a 24200 metros quadrados. Uma chácara retangular tem um alqueire e mede 100m de frente

sattari [20]

Answer:

b = 242 m

Explanation:

A = 24200 m²

a = 100 m

b = ?

A seguinte fórmula é aplicada

A = a*b

⇒ b = A / a

⇒ b = (24200 m²) / (100 m)

⇒ b = 242 m

5 0

3 years ago

Calculate the mass of air of density 1.2kgm-3 in a room of dimensions 8m by 6m by 4m.

77julia77 [94]

Answer:

230.4kg

Explanation:

volume of the room = l× b×h

volume= 8×6×4

volume=192m3

density= mass/volume

hence mass= density × volume

mass= 1.2kgm-3 × 192m3

mass= 230.4kg

5 0

2 years ago