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3 years ago

Describe what happens in a chemical reaction

Physics

2 answers:

ollegr [7]3 years ago

7 0

Answer:

LA REPUESTA CORRECTA ES

Explanation:

Lyrx [107]3 years ago

3 0

Chemical reaction, a process in which one or more substances, the reactants, are converted to one or more different substances, the products. Substances are either chemical elements or compounds. A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products

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A student is pushing a box across the room. To push the box three times farther, the student needs to do how much work?

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Answer:

Removing some of the books reduced the mass of the box, and less force was needed to push it across the floor.

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3 years ago

Hi guys can you help me with finding advantages with nuclear power?

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Answer:

Low-cost energy. Although building nuclear power plants has a high initial cost, it’s relatively cheap to produce energy from them and they have low operating costs.

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2 years ago

Read 2 more answers

When can you apply the idea that momentum is constant to solve a problem?

wlad13 [49]

It seems that you have missed the necessary options for us to answer this question, so I had to look for it. Anyway, here is the answer. You can apply the idea that momentum is constant to solve a problem when the system is not isolated but the time interval when the external forces are exerted is very small. Hope this helps.

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3 years ago

A 0.09 g honeybee acquires a charge of +23 pc while flying. The earth's electric field near the surface is typically (100 N/C, d

hodyreva [135]

Answer:

$2.6\times 10^{-5}$

Explanation:

Given:

$m$ = mass of the honeybee = 0.09 g = $9\times 10^{-5}\ kg$

$q$ = charge on the honeybee = 23 pC = $2.3\times 10^{-11}\ C$

$E$ = electric field near the surface of earth = 100 N/C

Assume:

$g$ = acceleration due to gravity = $9.8\ m/s^2$

$W$ = weight of the honeybee

$F$ = electric force on the honeybee

$R$ = ratio of the electric force and the weight of the honeybee

We know that

$F = qE\,\,\, and\,\,\, W = mg\\\therefore R = \dfrac{F}{W}\\\Rightarrow R = \dfrac{qE}{mg}\\\Rightarrow R = \dfrac{2.3\times 10^{-11}\ C\times 100 N/C}{9\times 10^{-5}\ kg\times 9.8\ m/s^2}\\\Rightarrow R = 2.6\times 10^{-6}$

So, the ration of the electric force on the bee to its weight is $2.6\times 10^{-6}$ .

On multiplying this ration by 10, the ratio becomes $2.6\times 10^{-5}$ .

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4 years ago

The dominant form of drag experienced by vehicles (bikes, cars, planes, etc.) at operating speeds is called form drag. It increa

trasher [3.6K]

Answer:

the power dissipated P = cd A v³

The speed increase percentage is 3.79

Explanation:

The power is defined as the change of work by the unit of time, as the work is the product of the force by the distance, we can rewrite the power, where the bold ones indicate vectors and the point is the scalar product.

P = F .v

In the current case, the force always opposes the speed, so the product is negative, which indicates a dissipative power.

Let's write the dissipation force and calculate

Fdrag = Cd A v²

P = Cd A v² v

P = cd A v³

this is the power dissipated

Second part

We write the expressions for the dissipated power for Po and P1

Po = Cd A vo³

P1 = 110 Po

P1 = Cd A v1³

We replace

110 Po = Cd A v13

110 (Cd A Vo³) = Cd A v1³

simplify

110 Vo3 = v13

v1 = ∛110 vo

We look for the one that increases the speed

(v1-vo) / vo = (∛110 vo-vo) / vo

(v1-vo) / vo = ∛110 -1

(v1-vo) / vo = 3.79

The speed increase percentage is 3.79

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3 years ago