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Mazyrski [523]
3 years ago
10

A chemist wishes to mix a 30% acid solution with a 65% acid solution to obtain 175 quarts of 55% acid solution . How many quarts

of each solution should be mixed toguether?
Mathematics
1 answer:
Eva8 [605]3 years ago
7 0

x = quarts of 30% acid solution

y = quarts of 65% solution

x + y = 175

Each quart of the 30% solution contributes 0.30x quarts of acid; similarly, each quart of the 65% solution contributes 0.65y quarts of acid. So

0.3x + 0.65y = 0.55*175 = 96.25

That is, the chemist wants 175 quarts of a new mixture with a 55% concentration of acid, which comes out to 95.25 total quarts of acid. The total amounts of acid from either sides of this equation must balance out.

Now solve for x and y:

x + y = 175  ==>  y = 175 - x

0.3x + 0.65y = 96.25  ==>  0.3x + 0.65(175 - x) = 96.25

==>  0.3x + 113.75 - 0.65x = 96.25

==>  17.5 = 0.35x

==>  x = 50  ==>  y = 125

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crimeas [40]
In the value of bonds, the symbol "M" means "thousands.
Therefore, 10 M = 10,000$

So, the customer bought a coupon with 10,000$ and the expected annual interest is 7.5% of the coupon's value.

Calculating the value of interest is simple, just multiply the interest rate (7.5%) by the original value of the coupon to know how much interest she will collect each year.

Interest collected each year = (7.5 / 100) x 1000 = 750$

5 0
3 years ago
A survey of 500 high school students was taken to determine their favorite chocolate candy. Of the 500 students surveyed, 42 lik
Step2247 [10]

Answer:

Step-by-step explanation:

Universal set

U = 500

The number that likes snickers

n(S) = 42

The number that like Twix.

n(T) = 110

The number that like Reeses

n(R) = 125

n(S n T) = 33

n(T n R) = 62

n(S n R) = 26

n( S n R n T) = 22

Then,

n(S n T) only = n(S n T) - n(S n R n T)

n(S n T) only =33 - 22 = 11

n(T n R) only = n(T n R) - n(S n R n T)

n(T n R) only =62 - 22 = 40

n(S n R) only = n(S n R) - n(S n R n T)

n(S n R) only =26 - 22 = 4.

Also,

n(S) only = n(S) - n(S n R) - n(S n T) only

n(S) only = 42 - 26 - 11 = 5

n(T) only = n(T) - n(T n R) - n(T n S) only

n(T) only = 110 - 62 - 11 = 37

n(R) only = n(R) - n(S n R) - n(R n T) only

n(R) only = 124 - 26 - 40 = 58

Then, to know if some student don't like any of the of chocolate,

Let know the number of students that like the chocolate candy

n(S) + n(T)only + n(T n R)only + n(R) only

42 + 37 + 40 + 58 = 177 students.

Therefore, the total students that like chocolate candy is 177, so those  that does not like any of them are

n(S U R U T)' = U – n(S U R U T)

n(S U R U T) = 500 - 177 = 323.

So, the question is how many student likes at most 2 kinds of these chocolates, this means that they can like exactly 2 or less or even none.

So, this category are

n(2 most) = n(S n T)only + n(R n T)only + n(S n R)only + n(s)only + n(T)only + n(R)only + n(S U R U T)'

n(2 most) = 11 + 40 + 4 + 5 + 37 + 58 + 323

n(2 most) = 478

The correct answer is E.

Check attachment for Venn diagram

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Morgarella [4.7K]
When it says per month, it means to multiply. In this case, the expression would be;

25x+50 

So however many months Fatima has spent at the gym, you would multiply that times 25 and add the initiation fee. Hope this helps. 

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Answer: perpendicular

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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