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disa [49]
3 years ago
10

If 3/8 of a class is absent what percentage of the class is present

Mathematics
1 answer:
ioda3 years ago
6 0

Answer:

37.5% of the class is present

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Now, you will consider Option 1, setting a maximum shower time of 10 minutes.
matrenka [14]

The maximum shower time is an illustration of mean and median, and the conclusion is to disagree with Blake's claim

<h3>How to interpret the shower time?</h3>

The question is incomplete, as the dataset (and the data elements) are not given.

So, I will answer this question using the following (assumed) dataset:

Shower time (in minutes): 6, 7, 7, 8, 8, 9, 9, 9, 12, 12, 12, 13, 15,

Calculate the mean:

Mean = Sum/Count

So, we have:

Mean = (6+ 7+ 7+ 8+ 8+ 9+ 9+ 9+ 12+ 12+ 12+ 13+ 15)/13

Mean = 9.8

The median is the middle element.

So, we have:

Median = 9

From the question, we have the following assumptions:

  • The shower time of students whose shower times are above 10 minutes, is 10 minutes
  • Other shower time remains unchanged.

So, the dataset becomes: 6, 7, 7, 8, 8, 9, 9, 9, 10, 10, 10, 10, 10

The mean is:

Mean = (6+ 7+ 7+ 8+ 8+ 9+ 9+ 9+ 10+ 10+ 10+ 10+ 10)/13

Mean = 8.7

The median is the middle element.

So, we have:

Median = 9

From the above computation, we have the following table:

               Initial    Final

Mean         9.8        8.7

Median       9         9

Notice that the mean value changed, but it did not go below 8 as claimed by Blake; while the median remains unchanged.

Hence, the conclusion is to disagree with Blake's claim

Read more about mean and median at:

brainly.com/question/14532771

#SPJ1

5 0
2 years ago
At 2:00 PM a car's speedometer reads 30 mi/h. At 2:10 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:10 the acce
Daniel [21]

Answer: If we define 2:00pm as our 0 in time; then:

at t= 0. the velocity is 30 mi/h.

then at t = 10m (or 1/6 hours) the velocity is 50mi/h

Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:

a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/h^{2}

Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)

So if v is differentiable, then there is a time T between 0h and 1/6h where v(T) = 120mi/h^{2}

5 0
3 years ago
Which number best represents the slope of the graphed line -5,-1/5,1/5,5
HACTEHA [7]

The slope of the line will be – 1/5. Then the correct option is B.

<h3>What is the equation of line?</h3>

The equation of line is given as

y = mx + c

Where m is the slope and c is the y-intercept.

Take two point from the graph.

(0, 2) and (1, –3)

Then the slope will be

m = (2 – (–3)) / (0 – 1)

m = 5 / (–1)

m = – 1/5

Then the correct option is B.

More about the equation of line link is given below.

brainly.com/question/21511618

#SPJ1

4 0
1 year ago
Solve. x² – 5x + 6 = 0<br><br> {–2, –3}<br><br> {2, 3}<br><br> {3, –2}<br><br> {5, –1}
ddd [48]
What 2 numbes multiply go get 6 and add to get -5
-6 and 1

(x-6)(x+1)=0
set to zero

x-6=0
x=6

x+1=0
x=-1

last one
4 0
3 years ago
If h(x)=x-9, find h(13)
Helen [10]

If you plug in h, the answer would be 13-9 which is 4.

6 0
3 years ago
Read 2 more answers
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