Answer:
3. x=21
4. x=28
5. x=35
Step-by-step explanation:
I did ths step by step on my whiteboard and I know my answers are right. Sorry if that sounds cocky.
Can I get brainliest?
Answer is 9/8 in or 1 1/8 in
Answer:
The correct option is B.
Step-by-step explanation:
Consider the diagram below.
It is a Venn diagram.
The diagram shows that all the natural numbers are contained in the set of all the whole numbers.
This implies that all natural numbers are whole numbers.
Then the statement best describing the relationship between whole numbers and natural numbers is:
(B) The diagram shows that natural numbers are a subset of whole numbers, because all natural numbers are whole numbers.
Thus, the correct option is B.
The answer is 9. When multiplying by decimals, you add up how many numbers are after the decimal in both numbers. So, the first on had 5, the second had 4.
5 + 4=9
Again, to find the local max/min, you need to find when the slope is equal to zero.
In this integral, you need to use the product rule.
f(x)=xe^(-3x)
The product rule states:
If f(x)=g(x)*h(x), then f'(x)=g(x)*h'(x)+g'(x)*h(x)
Let g(x) in this case be x and h(x) be e^(-3x)
Thus g'(x)=1 and h'(x)=-3e^(-3x)
Thus f'(x)=-3xe^(-3x)+e^(-3x)
Since we want slope to be zero, let's set f'(x)=0
0=-3xe^(-3x)+e^(-3x)
0=e^(-3x)(-3x+1)
since e^(-3x) can't equal zero(since it has a asymptote at y=0), we can cancel it to get
0=(-3x+1)
Thus at x=1/3 is an extrema
Now we plug that into f(x) to get f(1/3)=(1/3)e^(-3/3)=1/(3e)
Now we have to check if it's a max or a min.
To do this, we plug a value greater than the max x value into f'(x) and see if it's positive or negative.
f'(0)=-3(0)e^(-3(0))+e^(-3(0))=1, which is positive.
If the result is positive, it's a minimum.
Thus (1/3, 1/(3e)) is a minimum