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Amanda [17]
3 years ago
10

What is buffers and mention its importance?

Chemistry
1 answer:
GenaCL600 [577]3 years ago
5 0

Answer:

Buffer is the chemical substance that addition of acids and bases, maintaining constant environment,its called Buffer.

Explanation:

  • Buffers are use in the system to maintain the value of pH, and the contain the pH value is not to change.
  • Buffer maintain the body of pH for the optimal activity,and they are solution of pH constant.
  • Buffer in used in the lab and that to maintain growth of the micro tissues and the culture media.
  • Buffer are used in maintain necessary optimal reaction activity,determine the indicator of solution with pH.
  • Buffer capacity is that concentration to the buffering agent, is the very small increase,buffer capacity to the pH is 32% , of the maximum value of pH.
  • Buffers in a acid regions to the desired of that value to the particular buffer agent.
  • Buffers can be made from that a mixture of the base and acid, buffer can be a wide range of the obtained.
  • Buffers that the pH  calculation and they required to performed in the critic acid that the overlap over the buffer range.

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The highest atom economy

2CO + O₂ ⇒ 2CO₂

<h3>Further explanation</h3>

Given

The reaction for the production of CO₂

Required

The highest atom economy

Solution

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The general formula:

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<em>or </em>

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So a reaction that only produces one product will have the highest atomic value, namely the reaction in option C

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11. Fill in the blanks below for a general chemical reaction (products, reactants).
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In Lab 10 you make a stock solution of salicylic acid, and then four dilutions. The stock solution is made by diluting 5.00 ml o
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Answer:

Stock  solution =  1.25 *10^-3 M

Dilution 1 = 5*10^-4 M

Dilution 2= 3.75 * 10^-4 M

Dilution 3 = 2.5 *10^-4 M

Dilution 4 = 1.25 *10^-4 M

Explanation:

<u>Step 1:</u> Data given

The stock solution is made by diluting 5.00 ml of 1.250 x 10-2 M salicylic acid in 50.00 mL of solution.

<u>Step 2</u>: Calculate the concentration of the stock solution:

M1*V1 = M2*V2

⇒ with M1 = the initial concentration = 1.250 *10^-2 M

⇒ with V1 = 5 mL = 5*10^-3 L

⇒ with M2 = TO BE DETERMINED

⇒ with V2 = 50 mL = 50 *10^-3 L

M2 = (M1*V1)/V2

M2 = (1.250 *10^-2 * 5*10^-3 L) / 50 *10^-3

M2 = 0.00125 M = 1.25 *10^-3 M

<u>Step 3:</u> Calculate dilution 1

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 10 *10^-3)/(25*10^-3L)

M2 = 0.0005 M = 5*10^-4 M

<u>Step 4</u>: Calculate dilution 2

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 10 * 7.5*10^-3)/(25*10^-3)

M2 = 0.000375 M = 3.75 * 10^-4 M

<u>Step 5:</u> Calculate dilution 3

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 5*10^-3) /(25*10^-3)

M2 = 0.00025 M = 2.5 *10^-4 M

<u>Step 6</u>: Calculate dilution 4

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 2.5*10^-3)/(25*10^-3)

M2 = 0.000125 M = 1.25 *10^-4 M

5 0
3 years ago
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