(3y^7)^3 3^3*y^(7*3)
------------ = ------------------
9y^9 9*y^9
(3y^7)^3 3^3*y^(7*3) 27*y^21 (mult. together the exponents 3 and 7)
------------ = ------------------ = --------------
9y^9 9*y^9 9*y^9
That 27/9 reduces to 3. y^(21) / y^9 reduces to y^12.
Thus, we obtain 3*y^12 (answer)
Please do the next one, asking questions if need be, and showing your work.
x ≤ 12
Solution:
Let us take the number be x.
A number : x
A number divided by three : 
A number divided by three less two : 
A number divided by three less two is at most two : 
Now, simplify the inequality,

Add 2 on both sides of the inequality,


Multiply by 3 on both sides of the equation,


Hence x ≤ 12.
miren pongan enpeño en matematica