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Anon25 [30]
3 years ago
5

Is relation t a function? Is the inverse of relation t a function?

Mathematics
2 answers:
ElenaW [278]3 years ago
5 0
Relation t is a function and the inverse of relation t is a function because each domain element unique and it is paired to an unique range element.
bonufazy [111]3 years ago
3 0

<u>Answer:</u>

Hence, Relation t is a function. The inverse of relation t is a function.


<u>Step-by-step explanation:</u>

We are given the relation as:


x:    0 , 2 , 4 , 6


y:   -10 , -1 , 4 , 8

<em>Clearly from the y-values corresponding to the x-values we could see that each x has a single image (single y-value).</em>

Hence, the corresponding relation is a function.

Now we have to find whether the inverse of this relation is a function or not.

When we take the inverse of this function that is the y-values will behave as a pre-image and x-values as its image.

Hence we will see that corresponding to each y-value there is a unique image hence the inverse relation is also a function.

Hence, Relation t is a function. The inverse of relation t is a function.




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The volume of a rectangular prism can be found by multiplying the base area, B, times the height. If the volume of the prism is
PSYCHO15rus [73]

Answer:

Base (B) = /frac{15x² + 1 + 2}{x}

Step-by-step Explanation:

==>Given:

Dimensions of a rectangular prism are expressed as follow:

Volume (V) = 15x² + x + 2

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==>Required:

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==>Solution:

Volume (V) = Base (B) × Height (h)

15x² + x + 2 = B × x²

Divide both sides by x²

\frac{15x² + x + 2}{x²} = B[tex]Base (B) = /frac{15x² + 1 + 2}{x}

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3 years ago
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Rewrite the expression with a rational exponent as a radical expression.
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\sqrt{5}

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1 year ago
Read 2 more answers
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